Step-by-step explanation:
this is you answer solved.
520 dollars for 4 train tickets and 3 bus tickets.
Answer:
Each algebra book costs $60.
Step-by-step explanation:
A=bill for algebra books; S=bill for science books=A+$360
S+A=$3960 Substitute for S
A+$360+A=$3960 Subtract $360 from each side.
2A=$3600 Divide each side by 2.
A=$1800 The order for 30 algebra books cost $1800.
Individual book=A/30
individual book=$1800/30=$60 ANSWER: Each algebra book cost $60.
Answer:
Tn=a + (n-1)d
a= first term = 14
n= This is the term you're looking for... In this case... That's the 73rd term
d=Common difference (since its an AP)
d= second term - first term -- Or 3rd term - 2nd term = 23-14
d=9
T = 14 + (73-1)9
T= 14 + (72)9
T= 14 + 648
T=662.