Part A:

Given that the mattress is sold for 50% off of the retail price, let the retail price of the mattress be x, then

50% of x = 1200
⇒ 0.5x = 1200
⇒ x = 1200 / 0.5 = 2400

Therefore, the retail price of the mattress, before the discount is $2,400.

Part B:

Given that the store marks up the retail price to 150% of the wholesale price. Let the whole sale price be p, then

(100% + 150%) of p = 2400
250% of p = 2400
2.5p = 2400
p = 2400 / 2.5 = 960.

Therefore, the wholesale price, before the markup was $960

3 0

4 years ago

The basketball boosters are selling school t-shirts for $20 and warm up pants for $45. Last week they sold 100 items and collect

lesya [120]

They sold 76 t-shirts and 24 warm up pants.

Step-by-step explanation:

Cost of one t-shirt = $20

Cost of warm up pants = $45

Total sold = 100

Worth of sold items = $2600

Let,

x be the number of t-shirts.

y be the number of warm up pants.

According to statement;

x+y=100 Eqn 1

20x+45y=2600 Eqn 2

Multiplying Eqn 1 by 20

$20(x+y=100)\\20x+20y=2000\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(20x+45y)-(20x+20y)=2600-2000\\20x+45y-20x-20y=600\\25y=600\\$

Dividing both sides by 25

$\frac{25y}{25}=\frac{600}{25}\\y=24\\$

Putting y=24 in Eqn 1

$x+24=100\\x=100-24\\x=76$

They sold 76 t-shirts and 24 warm up pants.

Keywords: linear equations, elimination method

Learn more about elimination method at:

#LearnwithBrainly

5 0

3 years ago

Subtract 2 from the sum of j and 5

Vesnalui [34]

The answer is j+5-2
because sum means to add

5 0

3 years ago