A circle equation is :
( x - p )² + ( y - q )² = r², where p and q are coordinates of the center.
The position of the source is : ( - 6, - 4 ) and the range :
r² = 36 ⇒ r = 6
Answer:
(x+1)(x+8) When factoring squares whose squared coefficient is one the roots must add up to the coefficient of the slope and multiply out to the intercept value.
2(2y^4 + 7y^3 - 4y^2 -20)
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Y^2
4y^2 - 40/y^2 + 14y - 8
2(-2y^4 - 7y^3 + 4y^2 + 20)
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Y^2
Answer:
y = 2x -33
Step-by-step explanation:
The line segment from the center (6, 4) to the given point (16, -1) is a radius of the circle. It is perpendicular to the tangent. Hence you need to write the equation of a line through point (16, -1) that is perpendicular to the line through that point and (6, 4).
The slope of the radius is ...
... ∆y/∆x = (-1-4)/(16-6) = -5/10 = -1/2
The slope of the tangent is the negative reciprocal of that, so is ...
... m = -1/(-1/2) = 2
In point-slope form, the tangent line through (16, -1) is
... y = m(x -h) +k
... y = 2(x -16) +(-1)
Simplifying, this is ...
... y = 2x -33