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3 years ago

Determine whether each question is biased. Explain your answer.

2 answers:

8 0

Biased because the survey was conducted in a limited field of people aka health club which does not include other people, perhaps an unhealthy club? Or the people who are not a part of the health club? Or people who do not care about their health?

just olya [345]3 years ago

7 0

<h2>Answer:</h2>

A biased question is a question where you cannot expect a fair reply from the respondents. The people reply in a specific way and its mostly inclined towards one aspect or one direction of the survey.

Now the question is : A beverage company conducts a survey in the lobby of a health club to determine people's favorite beverage.

This question is definitely biased as first its conducted in a lobby where there will be few people and mostly they will be employees of the health club. They all an answer the same way.

Secondly, the survey is conducted in a health club and people who visit such clubs usually do not prefer sodas or beverages.

Rather this survey would have conducted with few hundred people from both groups - the healthy preference and non healthy preference. Then it would have been a fair survey.

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45 points! Please help me ASAP!

zlopas [31]

2 times 10^4 means 2 with 4 zeroes after it or 20000
4 times 10^6=4 with 6 zeros after it or 400000

compare

20000 and 4000000
we can see that 4000000 is 200 times of 20000
therefor the answer is C

we can also do
(4 times 10^6)/(2 times 10^4)=4/2 times (10^6)/(10^4)=2 times 10^2=200

answer is C

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2 years ago

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3 years ago

Which expression is equivalent to 5a+20? A: 5(5a+4). B: 5(a+4). C: 5(a+20). D: 5(a+1)

guajiro [1.7K]

Answer:

5(a+4)

Step-by-step explanation:

expression is equivalent to 5a+20

To get the equivalent expression we need to factor the given expression

5a+ 20

5a can be written as 5 * a

20 can be written as 5*2*2

WE can see that common factor is 5 for both 5a and 20

So GCF is 5

Now we factor out GCF 5

WE put 5 outside and write all the left of factors inside the parenthesis

5a +20

5 (a+2*2)

5(a+4)

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3 years ago

Help asap plz math isn't my thing

olga2289 [7]

<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>

➷ We have 2 points which we can use to figure out the slope

slope = difference in y values/ difference in x values

Substitute in the values you have:

0 - 5/ 3 - 0

slope = -5/3

The y intercept is simply where the line crosses the y axis

In this case, it is 5

Therefore, your equation is y = -5/3x + 5

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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2 years ago

In quadratic drag problem, the deceleration is proportional to the square of velocity

Mars2501 [29]

Part A

Given that $a= \frac{dv}{dt} =-kv^2$

Then,

$\int dv= -kv^2\int dt \\ \\ \Rightarrow v(t)=-kv^2t+c$

For $v(0)=v_0$ , then

$v(0)=-kv^2(0)+c=v_0 \\ \\ \Rightarrow c=v_0$

Thus, $v(t)=-kv(t)^2t+v_0$

For $v(t)= \frac{1}{2} v_0$ , we have

$\frac{1}{2} v_0=-k\left( \frac{1}{2} v_0\right)^2t+v_0 \\ \\ \Rightarrow \frac{1}{4} kv_0^2t=v_0- \frac{1}{2} v_0= \frac{1}{2} v_0 \\ \\ \Rightarrow kv_0t=2 \\ \\ \Rightarrow t= \frac{2}{kv_0}$

Part B

Recall that from part A,

$v(t)= \frac{dx}{dt} =-kv^2t+v_0 \\ \\ \Rightarrow dx=-kv^2tdt+v_0dt \\ \\ \Rightarrow\int dx=-kv^2\int tdt+v_0\int dt+a \\ \\ \Rightarrow x=- \frac{1}{2} kv^2t^2+v_0t+a$

Now, at initial position, t = 0 and $v=v_0$ , thus we have

$x=a$

and when the velocity drops to half its value, $v= \frac{1}{2} v_0$ and $t= \frac{2}{kv_0}$

Thus,

$x=- \frac{1}{2} k\left( \frac{1}{2} v_0\right)^2\left( \frac{2}{kv_0} \right)^2+v_0\left( \frac{2}{kv_0} \right)+a \\ \\ =- \frac{1}{2k} + \frac{2}{k} +a$

Thus, the distance the particle moved from its initial position to when its velocity drops to half its initial value is given by

$- \frac{1}{2k} + \frac{2}{k} +a-a \\ \\ = \frac{2}{k} - \frac{1}{2k} = \frac{3}{2k}$

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3 years ago