GIVING OUT BRAINLIEST!! All sacks of sugar have the same weight. All sacks of flour also have the same weight, but not necessari
ly the same as the weight of the sacks of sugar. Suppose that two sacks of sugar together with three sacks of flour weigh no more than $40$ pounds, and that the weight of a sack of flour is no more than $6$ pounds more than the weight of two sacks of sugar. What is the largest possible weight (in pounds) of a sack of flour?
2 answers:
Answer:
Let each sack of sugar weigh $s$ pounds and each sack of flour weigh $f$ pounds. Then from the given information, $2s + 3f \le 40$ and $f \le 2s + 6.$ Also, $s > 0$ and $f > 0.$ We graph these the intersection of these inequalities below.(document attached
We see that the largest possible value of $f$ occurs at the points where the lines $2s + 3f = 40$ and $f = 2s + 6$ intersect. Solving for $f,$ we find $f = \boxed{\frac{23}{2}}.$
Step-by-step explanation:
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