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ZanzabumX [31]
4 years ago
8

Daisies first summer job was working behind the counter at Dairy Queen he earned double time for any hours worked over 40 in a g

iven week what was the standard hourly pay if during one week he worked 51 hours and earned $189.10
Mathematics
1 answer:
FrozenT [24]4 years ago
8 0

Answer: the standard hourly pay is $3.05

Step-by-step explanation:

Let x represent the standard hourly pay that he gets for the first 40 hours.

Therefore, the total amount that he gets for the first 40 hours of work in a given week is 40x.

At Dairy Queen, he earned double time for any hours worked over 40 in a given week. This means that the hourly rate is 2x

If during one week, he worked 51 hours, it means that the overtime is 51 - 40 = 11 hours

Total amount earned for overtime is

11 × 2x = 22x

If the total amount that he earned for the week is $189.10, then

40x + 22x = 189.1

62x = 189.1

x = 189.1/62 = 3.05

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You have just opened a new dance club, Swing Haven, but are unsure of how high to set the cover charge (entrance fee). One week
aliya0001 [1]

Answer:

q = -6p + 104

Step-by-step explanation:

Linear function:

A linear function has the following format:

q = mp + b

In which m is the slope and b is the q-intercept.

One week you charged $4 per guest and averaged 80 guests per night. The next week you charged $10 per guest and averaged 44 guests per night.

This means that we have these following points: (4,80), (10,44).

Finding the slope:

With a pair of points, the slope is given by the change in q divided by the change in p.

Change in q: 44 - 80 = -36

Change in p: 10 - 4 = 6

Slope: m = \frac{-36}{6} = -6

So

q = -6p + b

Finding b:

We replace one of the points. Replacing (4,80).

q = -6p + b

80 = -6*4 + b

b = 104

So

q = -6p + 104

7 0
3 years ago
three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

=     3x + \frac{6}{5} = \frac{27}{4}

=     3x = \frac{27}{4} - \frac{6}{5}

( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

=     3x = \frac{111}{20}

=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

So, the weight of the equal bags are \frac{37}{20} and the weight of the third bag ( heavy one ) is \frac{37}{20} + \frac{6}{5} = \frac{37}{20} + \frac{24}{20} = \frac{61}{20}

1st bag =     \frac{37}{20} kg

2nd bag =  \frac{37}{20} kg

3rd bag =   \frac{61}{20} kg

Hope it helps...

7 0
3 years ago
Realy need help if you help thank you so much
stepladder [879]

Answer:

B

Step-by-step explanation:

Rate, in this case, is mph which can be written as miles/hours.

HTH :)

7 0
3 years ago
I need help, look at the picture.
worty [1.4K]
The order would be
A
C
B
7 0
3 years ago
How do I do problems 4-6
maria [59]
#4 is actually f(x) + 18. #5 is f(x) + 201, #5 is f(x) + 316.
3 0
3 years ago
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