Answer:
Inverse = (arcos x) / 2.
Step-by-step explanation:
y = cos 2x
2x= arcos y
x = (arcos y) / 2.
Inverse = (arcos x) / 2.
This looks like a simple arithmetic series. Each term is 7 greater than the previous term.
Therefore, the Nth term is 17 + 7N.
For example, the first term is 17 + 7*1 = 17 + 7 = 24.
The second term is 17 + 7*2 = 17 + 14 = 31
etc...
And the 500th term is 17 + 7 * 500 = 17 + 3500 = 3517
Answer:
Part A: The answer is B.
As vertically opposite angles are equal
x+10=4x-35
10=3x-35
45=3x
x=15
Part B: The answer is D.
We'll substitute in the value of X in one equation.
x+10
=15+10
=25
As the two angles are equal bot must be 25 degrees.
Answer:
x= 6.5 cm
Step-by-step explanation:
When a tangent line touches the circle, it forms a right angle triangle at that point
Apply the Pythagorean relationship in this case
Given that the height is = 20.2 cm = b
The hypotenuse is = c= x+14.7 cm
General formulae is;
a² +b² =c²
x² + 20.2² =( x+ 14.7)²
x² + 408.04= x² +14.7x+14.7x+216.09
x² + 408.04= x² + 29.4 x +216.09.........................collect like terms
x²-x² + 408.04-216.09= 29.4x
191.95= 29.4x-------------------------------divide by 29.4 t0 get x
191.95/29.4 =x
x=6.5 cm
Answer:
1. Opposite
2. angle-side-angle criterion
Step-by-step explanation:
Since ABCD is a parallelogram, the two pairs of <u>(opposite)</u> sides (AB¯ and CD¯, as well as AD¯ and BC¯) are congruent. Then, since ∠9 and ∠11 are vertical angles, it can be concluded that ∠9≅∠11. Since ABCD is a parallelogram, AB¯∥CD¯. Since ∠2 and ∠5 are alternate interior angles along these parallel lines, the Alternate Interior Angles Theorem allows that ∠2≅∠5. Since two angles of △AEB are congruent to two angles of △CED, the Third Angles Theorem supports that ∠8≅∠3. Therefore, using the <u>(angle-side-angle criterion)</u>, it can be stated that △AEB≅△CED. Then, applying the definition of congruent triangles, it can be stated that AE¯≅CE¯, which makes E the midpoint of AC¯. Use a similar argument to prove that △AED≅△CEB; then it can be concluded that E is also the midpoint of BD¯. Since the midpoint of both line segments is the same point, the segments bisect each other by definition. Match each number (1 and 2) with the word or phrase that correctly fills in the corresponding blank in the proof.
A parallelogram posses the following features:
1. The opposite sides are parallel.
2. The opposite sides are congruent.
3. It has supplementary consecutive angles.
4. The diagonals bisect each other.
