<span>Let An
be the likely number of rolls for Andrea to arrive at 100
or more, given that she is n
away from the target of 100
(which means her current total is 100 - n ).
Then we get the recurrence relation</span>
An = 1 + (1/6) (An-1 + An-2 + An-3 +
An-4 + An-5 + An – 6)
<span>and the initial conditions A0
= A-1 = A-2 = A-3 = A-4 = A-5 = 0. This results in A100 = 29.0476 as the amount
of expected rolls that Andrea has to make.</span>
<span>Now let Rn
to be expected amount of rolls for Raleigh to arrive at 100 or more, given than
he is also
n away from the target of 100.
Now the recurrence relation is:</span>
Rn = 1 + (1/2) (Rn-1 + Rn-6)
with the initial conditions R0 = R-1 =
R-2 = R-3 = R-4 = R-5 = 0. This gives us R100 = 29.1837 as the expected amount
of rolls for Raleigh.
Therefore Andrea has to make less number of rolls thus she
is expected to win.
Winner: Andrea
S = 3w - 66
s = 899
899 = 3w - 66 <== ur equation....just solve for w, the wholesale price
Answer:
y=2x+4
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(10-6)/(3-1)
m=4/2
m=2
y-y1=m(x-x1)
y-6=2(x-1)
y=2x-2+6
y=2x+4
Answer:
"The product of a number and 8"=8n
8n is the expression, evaluated when n=4 is:
8(4)=32
Step-by-step explanation:
Answer:
in
Step-by-step explanation:
That's the correct answer :)