Answer:
everyone gets 5 pieces and the rest gets thrown out
Step-by-step explanation:
29/5=5.8
but obviously ur not gonna break the candy into .8 so everyone just gets 5 so its even
Answer:
Um the picture isn´t very clear it is hard to see it.
Step-by-step explanation:
at least on my end it is.
Answer:
x1 =2-5i*sqrt(2)
x2 =2+5i*sqrt(2)
Step-by-step explanation:
-x^2 +4x-54=0 (quadratic equation)
a=-1, b=4, c=-54
x1=(-b+sqrt(b^2-4ac))/2a
x1=(-4+sqrt(4^2 - 4*(-1)(-54))/2*(-1)
x1=(-4+sqrt(16-216))/(-2)
x1 =(-4+sqrt(-200))/(-2)
x1 =(-4+sqrt(200i^2))/(-2) i^2=-1
x1 =(-4+sqrt(100*2*i^2))/(-2)
x1 =(-4+10i*sqrt(2))/(-2)
x1 =2-5i*sqrt(2)
x2 =(-b-sqrt(b^2-4ac))/2a
x2 =(-4-10i*sqrt(2))/(-2)
x2 =2+5i*sqrt(2)
Answer: The correct option is (B) 24 : 25.
Step-by-step explanation: Given that the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2 : 3.
We are to find the ratio of the area of R to the area of S.
Let 2x, 3x be the sides of rectangle R and y be the side of square S.
Then, according to the given information, we have

Therefore, the ratio of the area of R to the area of S is
![\dfrac{2x\times3x}{y\times y}\\\\\\=\dfrac{5x^2}{y^2}\\\\\\=6\left(\dfrac{x}{y}\right)^2\\\\\\=6\times\left(\dfrac{2}{5}\right)^2~~~~~~~~~~~[\textup{Using equation (i)}]\\\\\\=\dfrac{24}{25}\\\\=24:25.](https://tex.z-dn.net/?f=%5Cdfrac%7B2x%5Ctimes3x%7D%7By%5Ctimes%20y%7D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B5x%5E2%7D%7By%5E2%7D%5C%5C%5C%5C%5C%5C%3D6%5Cleft%28%5Cdfrac%7Bx%7D%7By%7D%5Cright%29%5E2%5C%5C%5C%5C%5C%5C%3D6%5Ctimes%5Cleft%28%5Cdfrac%7B2%7D%7B5%7D%5Cright%29%5E2~~~~~~~~~~~%5B%5Ctextup%7BUsing%20equation%20%28i%29%7D%5D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B24%7D%7B25%7D%5C%5C%5C%5C%3D24%3A25.)
Thus, the required ratio of the area of R to the area of S is 24 : 25.
Option (B) is CORRECT.