Given:
A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7).
Rule of rotation is 
.
To find:
The vertices after rotation.
Solution:
We know that, means 90 degrees counterclockwise rotation around the origin.
So, the rule of rotation is defined as
Using this rule, we get
Therefore, the required vertices after rotation are W'(5,3), X'(3,1),Y'(5,-1) and Z'(7,1).
Answer:
7i + 11j
Step-by-step explanation:
DE = 8i + 6j - i + 5j
= 7i + 11j
Answer:
4x^2 +2x +16
Step-by-step explanation:
7x2 + 4x + 10) - (3x2 + 2x - 6)
Distribute the minus sign
7x2 + 4x + 10) - 3x2 - 2x + 6
Combine like terms
7x2 + 4x + 10)
- 3x2 - 2x + 6
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4x^2 +2x +16
A. Equation of line l: y = mx + 20 where m = y' = 1- (1/250)x
At the point Q, The equation of the line equals the equation of the parabola.
So (1-x/250)x + 20 = x - x^2/500
20 = x^2/250 - x^2/500 = x^2/500
x = sqrt(20*500) = 100ft
B. m = 1 - 100/250 = 3/5.
<span>Equation of line L is y = 3/5x + 20
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C) If a spotlight is located at the x intercept of line L (-33 1/3,0), its light will go only above line L past the point where line L is tangent to the hill at (100,80) because the hill blocks the light below the tangent line.
<span>The highest point on the equation of y = x - x²/500 is at (250,125), so a tree 50 feet tall at that location would reach up to (250,175). The tangent line goes through (250,170), so the top 5 feet of the tree would be above the tangent line, in the glow of the spotlight.
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