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2 years ago

Solve for X 3(x + 7) < 7(x + 2)

Mathematics

2 answers:

antiseptic1488 [7]2 years ago

7 0

$\\ \tt\hookrightarrow 3(x+7)$

$\\ \tt\hookrightarrow 3x+21$

$\\ \tt\hookrightarrow 3x-7x$

$\\ \tt\hookrightarrow -4x$

$\\ \tt\hookrightarrow 4x>7$

$\\ \tt\hookrightarrow x>7/4$

$\\ \tt\hookrightarrow x\in(\dfrac{7}{4},\infty)$

Furkat [3]2 years ago

5 0

Answer:

x > 7/4

Step-by-step explanation:

3(x + 7) < 7(x + 2)

Expand brackets: 3x + 21 < 7x + 14

Subtract 14 from both sides: 3x +7 < 7x

Subtract 3x from both sides: 7 < 4x

Divide both sides by 4: 7/4 < x

Therefore x > 7/4

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