Question

Solve for X 3(x + 7) < 7(x + 2)

Answer 1

$\\ \tt\hookrightarrow 3(x+7)$

$\\ \tt\hookrightarrow 3x+21$

$\\ \tt\hookrightarrow 3x-7x$

$\\ \tt\hookrightarrow -4x$

$\\ \tt\hookrightarrow 4x>7$

$\\ \tt\hookrightarrow x>7/4$

$\\ \tt\hookrightarrow x\in(\dfrac{7}{4},\infty)$

Answer 2

Answer:

x > 7/4

Step-by-step explanation:

3(x + 7) < 7(x + 2)

Expand brackets:                 3x + 21 < 7x + 14

Subtract 14 from both sides:  3x +7 < 7x

Subtract 3x from both sides:         7 < 4x

Divide both sides by 4:              7/4 < x

Therefore x > 7/4