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Vladimir79 [104]
2 years ago
13

Solve for X 3(x + 7) < 7(x + 2)

Mathematics
2 answers:
antiseptic1488 [7]2 years ago
7 0

\\ \tt\hookrightarrow 3(x+7)

\\ \tt\hookrightarrow 3x+21

\\ \tt\hookrightarrow 3x-7x

\\ \tt\hookrightarrow -4x

\\ \tt\hookrightarrow 4x>7

\\ \tt\hookrightarrow x>7/4

\\ \tt\hookrightarrow x\in(\dfrac{7}{4},\infty)

Furkat [3]2 years ago
5 0

Answer:

x > 7/4

Step-by-step explanation:

3(x + 7) < 7(x + 2)

Expand brackets:                 3x + 21 < 7x + 14

Subtract 14 from both sides:  3x +7 < 7x

Subtract 3x from both sides:         7 < 4x

Divide both sides by 4:              7/4 < x

Therefore x > 7/4

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Step-by-step explanation:

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