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makkiz [27]
3 years ago
15

A random variable r is normally distributed with a mean of 7 and a standard deviation of 1.5. Find the value of w so that P (8.8

Mathematics
1 answer:
a_sh-v [17]3 years ago
4 0

Answer:

The answer is explained below

Step-by-step explanation:

Given that:

mean (μ) = 7 and standard deviation (σ) = 1.5.

The z score is used in statistic used to measure the number of standard deviation by which the raw score is above or below the mean value. It is given by:

z=\frac{x-\mu}{\sigma}, where\ x\ is\ the \ raw\ score

To find the Probability that x < 8.8, we first find the z score using:

z = \frac{x-\mu}{\sigma}=\frac{8.8-7}{1.5}=1.2

From the z tables, P(x < 8.8) = P(z < 1.2) = 0.8849 = 88.49%

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Evaluate the expression when a=- 7 and x=3.<br> a-8x
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Answer:

-31

Step-by-step explanation:

a - 8x will change to (-7) - 8(3) = -31

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3 years ago
How do you do this I need help
Liula [17]
The answer is 2 and 5/6                                                                                            
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Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a
just olya [345]

Answer:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and X \sim Bin(n=600, p =0.4)

And we want this probability:

P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.&#10;[tex]np=600*0.4=240\geq 10

n(1-p)=600*(1-0.4)=360 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=600*0.4=240

\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12

And then X \sim N (\mu = 240, \sigma= 12)

And we are interested on the following probability:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

6 0
3 years ago
AT the local zoo, the aquarium can be seen from the Reptile Room and the Amphibian Arena. What is the total area of both rooms a
BartSMP [9]

Answer:

The total area of both rooms and the aquarium is equal to 10,932 ft²

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

the length sides of Aquarium are

(83-32) x (72-52)-----> 51 ft x 20 ft

Area reptile room=(83*72)-area of aquarium----> 83*72-51*20---> 4,956 ft²

[ total area of both rooms]=2*4,956-----> 9,912 ft²

I'm assuming that the two areas are equal

Area of aquarium=51*20=1,020 ft²

therefore

the total area of both rooms and the aquarium is equal to

9,912 ft²+1,020 ft²=10,932 ft²

6 0
3 years ago
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