Question

A random variable r is normally distributed with a mean of 7 and a standard deviation of 1.5. Find the value of w so that P (8.8

Answer 1

Answer:

The answer is explained below

Step-by-step explanation:

Given that:

mean (μ) = 7 and standard deviation (σ) = 1.5.

The z score is used in statistic used to measure the number of standard deviation by which the raw score is above or below the mean value. It is given by:

$z=\frac{x-\mu}{\sigma}, where\ x\ is\ the \ raw\ score$

To find the Probability that x < 8.8, we first find the z score using:

$z = \frac{x-\mu}{\sigma}=\frac{8.8-7}{1.5}=1.2$

From the z tables, P(x < 8.8) = P(z < 1.2) = 0.8849 = 88.49%