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Alborosie
3 years ago
11

There are about 4200 college presidents in the United States, and they have annual incomes with a distribution that is skewed in

stead of being normal. Many different samples of 40 college presidents are randomly selected, and the mean annual income is computed for each sample. What is the approximate shape of the sample means?
Mathematics
1 answer:
forsale [732]3 years ago
3 0
<span>Because a mean is an average, the means of each of the samples of 40 college presidents' incomes will have less of a skew than the actual income distribution in dollars of all of them. That is because outliers, like a president who is paid $2 million a year, will be averaged in with many others who are paid less. The shape of the curve of the means will depend upon how many different samples of 40 presidents are included, with the shape becoming more bell-like (normal distribution) the more random samples are included. Another consideration is how often the outliers are included and how big the income skew is that you start with. For example, if 2 college presidents are earning $2 million a year and the other 4,198 are earning $200,000 or less then the shape of your curve will depend greatly upon the number of times those two high earners are randomly selected and factored into the mean.</span>
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5.1 kilometers to meters and centimeters
Snezhnost [94]
Hey there 

1 km = 1000 meters 
So 5 km will equal 5000 meters 
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5.1 km = 5100 meters 

<span>100,000 centimeters = 1 kilometer 
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Hope this helps  


7 0
3 years ago
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Scorpion4ik [409]

Answer:

6

General Formulas and Concepts:

<u>Algebra I</u>

  • Terms/Coefficients/Degrees

Step-by-step explanation:

<u>Step 1: Define</u>

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<u>Step 2 Identify</u>

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7 0
3 years ago
Enrollment at ELAC decreased by 5%, or 600 people, the year. How many people were enrolled last year?
babymother [125]

Answer:

12,000.

Step-by-step explanation:

Let x be the number of people that were enrolled last year.

We have been given that enrollment at ELAC decreased by 5%, or 600 people, the year. We are asked to find the number of people that were enrolled last year.

We can set as equation such that 5% of x equals 600.

\frac{5}{100}\cdot x=600

0.05x=600

\frac{0.05x}{0.05}=\frac{600}{0.05}

x=12,000

Therefore, 12,000 people were enrolled last year.

7 0
3 years ago
What is £300 divided into a ratio of 3:7
3241004551 [841]
A) sum 3 + 7 =10
b) divide <span> £</span>300 ÷ 10 = <span> £</span>30
c) multiply:
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     7 x 30 = <span> £</span>210

Values are:  £90 and <span> £210</span>



5 0
3 years ago
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adell [148]
25 + 25 <<<<< I think .
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