So it is asking you to group like term so
x terms can be grouped/added/subtracted to other x terms, but not to x^2 or x^3 terms
x^2 terms to x^2 and so on so
1. 9-3k+5k=
9+(5k-3k)=
9+2k
2. k^2+2k+4k=
k^2+(2k+4k)=
k^2+6k=
Option c. is the correct answer.
Answer:
first method
<u>2</u><u>2</u>=<u>5</u>
7. x
we cross multiply to get
<u>2</u><u>2</u><u>x</u>= <u>5</u><u>×</u><u>7</u>
22. 22.
x= <u>3</u><u>5</u>
22
=1.59
second method
<u>2</u><u>2</u>=<u>5</u>
7. x
we multiply the denominators to get 7x
then we multiply each term by 7x
7x×<u>2</u><u>2</u> = <u>5</u>×7x
7. x
here the 7 and 7 will cancel out and the x and x will cancel out to get
<u>2</u><u>2</u><u>x</u>= <u>3</u><u>5</u>
22. 22
= 1.59
<span>Break down every term into prime factors. ...Look for factors that appear in every single term to determine the GCF. ...Factor the GCF out from every term in front of parentheses, and leave the remnants inside the parentheses. ...<span>Multiply out to simplify each term. </span></span>
So, u would start by expanding the bracket and ignoring the 2 at the moment.
(x+9)(x+9)= x^2-18x+81(using the foil method!
Then u would put 2 at the front to get:
2(x^2+18x+81)
= 2x^2+36x+162