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motikmotik
3 years ago
5

Give a quick estimate of the area of a rectangle with length 114 in. And width 92 in. ?

Mathematics
1 answer:
Inessa05 [86]3 years ago
7 0
An estimation is made by slightly rounding the numbers, then multiplying , adding, subtracting, or dividing.
In this case , to make an estimate, I would round 114 to 100, and 92 to 90... 100 x 90 = 9,000 sq in
You can of course round closer than that, depending on how accurate you want it to be, but the exact answer is 10,488, Wich you can round to 10,000 or 10,500
Hope this helped :)
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On the planet of Mercury, 4-year-olds average 3 hours a day unsupervised. Most of the unsupervised children live in rural areas,
erastova [34]

Answer:

a

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b

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c

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Step-by-step explanation:

From the question we are told that

   The population mean is  \mu =  3 \  hours

   The standard deviation is  \sigma  =  1.4 \ hours

Generally given from the question that the amount of time spent alone by the population size is normally distributed then then the distribution of X (i.e the amount of time spent by the sample size (the one Mercurian)) will be normally distributed

  Generally the probability that the child spend less than one hour in a day is mathematically represented as

        P(X  <  1.4) =  P(\frac{X - \mu}{\sigma} < \frac{1.4 - \mu}{\sigma}   )

Here \frac{X - \mu}{\sigma }  =  Z (The\ standardized\ value\ of\  X)

So

      P(X  <  1.4) =  P(Z < \frac{1.4 - 3.0}{1.4}   )

     P(X  <  1.4) =  P(Z < -1.1429  )

From the z-table the value of  

        P(Z < -1.1429  )=0.12654

So     P(X  <  1.4) = 0.12654

Generally the percentage of children that spends over 3.5 hours unsupervised is mathematically represented as

        P(X  >  3.5) =  P(\frac{X - \mu}{\sigma} > \frac{3.5 - \mu}{\sigma}   )

        P(X >  3.5) =  P(Z > \frac{3.5 - 3.0}{1.4}   )

        P(X >  3.5) =  P(Z > 0.3571  )

From the z-table the value of  

        P(Z >0.3571  )=0.36051

So     P(X  >  3.5) = 0.36051

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