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vichka [17]
4 years ago
10

How you can use physical properties to compare substances.

Biology
1 answer:
Alex4 years ago
8 0
To proceed scientifically, you could measure several properties of the unknown liquid and compare them with the properties of known substances. You might observe and measure such properties as color, odor, texture, density, boiling point, and freezing point.
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Scrat [10]

Answer:

Abstract. DNA polymerase I (pol I) processes RNA primers during lagging-strand synthesis and fills small gaps during DNA repair reactions. However, it is unclear how pol I and pol III work together during replication and repair or how extensive pol I processing of Okazaki fragments is in vivo

Explanation:

3 0
3 years ago
To what extent has the presence of a true coelom in animals changed over the course of evolution?
tankabanditka [31]

Option D is the correct answer.

To what extent has the presence of a true coelom in animals changed over the course of evolution?  

A coelom is a body cavity that is formed from the mesoderm tissue.

Option D - The presence or absence of a true coelom appears to have changed multiple times during the course of evolution.

3 0
3 years ago
Read 2 more answers
Whats the function of the occipital lobe
wolverine [178]

Answer:

The occipital lobe is the visual processing area of the brain. It is associated with visuospatial processing, distance and depth perception, color determination, object and face recognition, and memory formation.

6 0
3 years ago
An autosomal recessive disease has an incidence of 1/10,000. What is the approximate frequency of heterozygote carriers for this
goblinko [34]

Answer:

Option B

Explanation:

Given

Number of incidences or frequency of an autosomal recessive disease = \frac{1}{10000}

As per Hardy Weinberg's equation, frequency of a recessive genotype is q^{2}

q = \sqrt{\frac{1}{10000} }\\ q = \frac{1}{100}

As per first equation of Hardy Weinberg's -

p+q=1

so ,

p = 1-q\\p = 1-\frac{1}{100}\\p = \frac{99}{100}

p^2 = (\frac{99}{100})^2\\p^2 =\frac{9801}{1000}

As per second equation of Hardy Weinberg's -

p^{2} + q^{2} + 2pq=1

Substituting the given values in above equation, we get -

\frac{9801}{10000} + \frac{1}{100} + 2pq=1\\2pq = 1-(\frac{9801}{10000} + \frac{1}{100})\\2pq = 0.99%\\OR[tex]2pq=1%

2pq = \frac{1}{100}

Hence, option B is correct.

8 0
3 years ago
Write a lab report for this lesson’s lab. Be sure that your report:
nordsb [41]

Answer:

We don't know what your lab is about so we can't help answer

3 0
3 years ago
Read 2 more answers
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