<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>
➷ 40 inches = 3.33333
Area = length x width
Substitute the values:
Area = 9 x 3.33333
Solve:
Area = 30ft^2
<h3><u>
✽</u></h3>
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
↬ <u>ʜᴀɴɴᴀʜ</u> ♡
1
:x
2
+y
2
−6x−9y+13=0
(x−3)
2
+(y−
2
9
)
2
−9−
4
81
+13=0
(x−3)
2
+(y−
2
9
)
2
=
4
65
Here,
r
1
=
2
65
C
1
=(3,
2
9
)
Equation of another circle-
S
2
:x
2
+y
2
−2x−16y=0
(x−1)
2
+(y−8)
2
−1−64=0
(x−1)
2
+(y−8)
2
=65
Here,
r
2
=
65
C
2
=(1,8)
Distance between the centre of two circles-
C
1
C
2
=
(3−1)
2
+(8−
2
9
)
2
C
1
C
2
=
4+
4
49
=
2
65
∣r
2
−r
1
∣=
∣
∣
∣
∣
∣
∣
65
−
2
65
∣
∣
∣
∣
∣
∣
=
2
65
∵C
1
C
2
=∣r
1
−r
2
∣
Thus the two circles touches each other internally.
Since the circle touches each other internally. The point of contact P divides C
1
C
2
externally in the ratio r
1
:r
2
, i.e.,
2
65
:
65
=1:2
Therefore, coordinates of P are-
⎝
⎜
⎜
⎜
⎜
⎜
⎛
1−2
1(1)−2(3)
,
1−2
1(8)−2(
2
9
)
⎠
⎟
⎟
⎟
⎟
⎟
⎞
=(5,1)
Therefore,
Equation of common tangent is-
S
1
−S
2
=0
(5x+y−6(
2
x+5
)−9(
2
y+1
)+13)−(5x+y−2(
2
x+5
)−16(
2
y+1
))=0
2
−6x−9y−13
+x+8y+13=0
4x−7y−13=0
Hence the point of contact is (5,1) and the equation of common tangent is 4x−7y−13=0.
Answer: I believe that the answer is all of the above
Step-by-step explanation:
Answer:
Volume of given figure = 113.12 cm²
Step-by-step explanation:
Given:
Radius of cylinder = 4/2 = 2cm
Radius of cone = 4/2 = 2 cm
Height of cylinder = 7 cm
Height of cone = 6 cm
Find:
Volume of given figure
Computation:
Volume of given figure = Volume of cylinder + Volume of cone
Volume of given figure = πr²h + (1/3)πr²h
Volume of given figure = (22/7)(2)²(7) + (1/3)(22/7)(2)²(6)
Volume of given figure = (22/7)(4)(7) + (1/3)(22/7)(4)(6)
Volume of given figure = (22)(4) + (22/7)(4)(2)
Volume of given figure = 88 + 25.14
Volume of given figure = 113.12 cm²
