Answer:
x = 3 ± 
or
x = 3 + , x = 3 -
Step-by-step explanation:
given f(x) = 2(x - 3)^2 - 8, find when f(x) = 40
So, we plug in 40 for f(x) in the 1st equation and solve for x. (Aim to got x on its own)
40 = 2 (x - 3)^2 - 8
+ 8 + 8
-----------------------------
48 = 2 (x - 3)^2
/2 /2
-----------------------------
24 = (x - 3)^2
square root both sides
--------------------
= x - 3
x = 3 ±
Las razones de los lados de un triángulo rectángulo se llaman razones trigonométricas.
Espero te ayude :)
After manipulating above equation we get, 2x^2 - 7x - 8= 0. Discriminant= b^2 - 4ac = (-7)^2 - 4(2)(-8) = 113>0. So there are 2 real roots :)
Split 
into two component segments, 
and 
, parameterized by
respectively, with 
, where 
.
We have
where 
so the line integral becomes
