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Mathematics

1 answer:

Anvisha [2.4K]3 years ago

3 0

Answer:

Step-by-step explanation:

Identity property of Multiplication: A

Associative property of Addition: F

Identity property of Addition: C, E

Commutative property of Addition: D

Associative property of Multiplication: B

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Which angle number is a vertical angle to

VMariaS [17]

Answer:

Angle 7 or angle DHG

Step-by-step explanation:

Vertical means the opposite angle, or in dictionary definition means each of the pairs of opposite angles made by two intersecting lines. So the vertical angle to angle LHI (angle 9) will be angle DHG (angle 7)

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3 years ago

Jacey obtains a 30-year 6/2 ARM at 4% with a 2/6 cap structure in the amount of $224,500. What is the monthly payment during the

beks73 [17]

In this case we have an ARM fixed for 6 years and adjust after the initial first 6 years every 2 years after. The basic idea behind a ARM is that the interest changes periodically, but since our ARM is fixed for 6 years, our going to calculate the monthly payment during the initial period using the formula: $m= \frac{P( \frac{r}{12}) }{1-(1+ \frac{r}{12})^{-12t} }$
where
$m$ is the monthly payment
$P$ is the amount
$r$ is the interest rate in decimal form
$t$ is the number years

First we need to convert our interest rate of 4% to decimal form by dividing it by 100%:
$\frac{4}{100} =0.04$
We also know from our question that $P=224500$ and $t=30$ , so lets replace those values into our formula to find the monthly payment:
$m= \frac{224500( \frac{0.04}{12}) }{1-(1+ \frac{0.04}{12})^{-(12)(30)} }$
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We can conclude that the monthly payment during the initial period is $1071.58<span />

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3 years ago

A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have