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3 years ago

How to simplify 9+5(4x+4)

2 answers:

5 0

Use PEMDAS. Parenthesis, Exponents, Multiply, Divide, Addition, Subtraction.
So, you'd distribute 5 into the parenthesis, leaving you with 9+20x+20, then add like terms. 20x+29

True [87]3 years ago

5 0

9+5(4x+4)=
9+20x+20=0
20x+29=0

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An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a d

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Answer:

The probability of event A is $\frac{7}{11}$ .

The probability of event B is $\frac{6}{11}$ .

Step-by-step explanation:

The sample space of rolling a fair six-sided dice is as follows:

S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

Now consider the experiment of the computing the sum of the two rolls as follows:

X = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

Number of total outcomes, N = 11.

The probability of an event E is the ratio of the number of favorable outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

The event A is defined as the sum is greater than 5.

The sample space of A is:

A = {6, 7, 8, 9, 10, 11, 12}

n (A) = 7

Compute the probability of event A as follows:

$P(A)=\frac{n(A)}{N}=\frac{7}{11}$

Thus, the probability of event A is $\frac{7}{11}$ .

The event B is defined as the sum is an even number.

The sample space of B is:

B = {2, 4, 6, 8, 10, 12}

n (B) = 6

Compute the probability of event B as follows:

$P(B)=\frac{n(B)}{N}=\frac{6}{11}$

Thus, the probability of event B is $\frac{6}{11}$ .

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3 years ago

Last year, a person wrote 123 checks. Let the random variable x represent the number of checks he wrote in one day, and assume

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Answer:The mean number of checks written per day = 0.3370

The standard deviation = 0.5805

The variance = 0.3370

Step-by-step explanation:

Let the random variable x represent the number of checks he wrote in one day.

Given : The number of checks written in last year = 123

Let the number of days in the year must be 365.

Now, the mean number of checks written per day will be :-

$\lambda=\dfrac{123}{365}=0.33698630137\approx0.3370$

We know that in Poisson distribution , the variance is equals to the mean value .

$\text{Thus , Variance }=\sigma^2= 0.3370$

$\Rightarrow\ \sigma=\sqrt{0.3370}=0.580517010948\approx0.5805$

Thus, Standard deviation = 0.5805

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3 years ago

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So one way is to have a number close to 7
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3 years ago

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Answer:

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Step-by-step explanation:

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-13 is the only value that appears in the range set and in the multiple choice solutions. Therefore, the answer is C. -13

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3 years ago

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blondinia [14]

Answer:

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Step-by-step explanation:

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