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SOVA2 [1]
3 years ago
6

If you drew a line segment from the point when Kiley arrived at the airport to the point when she reached the waiting area near

the gate, at what point would the line segment end?
Hi please help me if you can, I've been stuck on this for a few days-

This may be useful- at the airport, the walk from the car to the waiting area by the gate -- 3/4 hours
Mathematics
2 answers:
erastova [34]3 years ago
4 0

Answer:  THE ASAWER IS 2HR

Setler79 [48]3 years ago
3 0
2 hours is the answer
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Please help due at the end of class
Klio2033 [76]

Answer:

B; or "a > -2"

Step-by-step explanation:

If solved by order of operations:

- divide both sides by 13

- 13 will cancel out on the left side and the when -26 will be divided by 13 the answer will be "-2"

- This leaves with the answer of "x > -2"

Hope this helps!

3 0
3 years ago
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What is the vertical asymptote for this function?<br> y=1/x-2
nataly862011 [7]

Answer: x = 0

Step-by-step explanation: so x = 0 is the equation of the vertical asymptote, and 0 must be left out of the domain: (−∞,0)U(0,∞) in interval notation.

8 0
3 years ago
You drive 30 miles due east in a half hour. Then, you turn left and drive 30 miles north in 1 hour. What are your average speed
garri49 [273]
Original position: P1=(0,0)
<span>You drive 30 miles due east in a half hour: x=+30 miles, t1=1/2 hour=0.5 hours
</span><span>Then, you turn left and drive 30 miles north in 1 hour: y=+30 miles, t2=1 hour
Rectangular coordinates of final position: P2=(x,y)→P2=(30,30)
Total time: t=t1+t2=0.5 hours+1 hour→t=1.5 hours

Average speed: S ave=d/t
Total distance: d=x+y=30 miles+30 miles→d=60 miles
S ave = 60 miles / (1.5 hours)
S ave = 40 miles/hour

Velocity is a vector, the magnitude of this vector is the magnitude of the vector of change of position dividing by the total time t
The vector of change of position: s=P1-P2=(30,30)-(0,0)=(30-0,30-0)→
s=(30,30) 
Magnitude of vector s=sqrt[30^2+30^2]=sqrt[30^2*2]=sqrt[30^2]*sqrt(2)
Magnitude of vector s=30*sqrt(2) miles

Magnitude of velocity vector = Magnitud of vector s / t
Magnitude of velocity vector = [30*sqrt(2) miles] / (1.5 hours)
Magnitude of velocity vector = 20*sqrt(2) miles / hour
Magnitude of velocity vector=20*1.4142 miles / hour
Magnitude of velocity vector=28.284 miles/hour

Polar coordinates of your position=(r, theta)
r=Magnitude of vector s=30*sqrt(2) miles
theta=tan^(-1) (y/x) = tan^(-1) [(30 miles) / (30 miles)]
theta=tan^(-1) (1)→theta=45°=Pi/4 (Pi=3.1416)
Polar coordinates of your position: ( 30*sqrt(2) miles, 45°)
Polar coordinate of your position: ( 30*sqrt(2) miles, Pi/4 )

Answers:
Average speed: 40 miles / hour
Velocity: 20*sqrt(2) miles / hour = 28.284 miles / hour
Rectangular coordinates of your position = (30,30)
Polar coordinates of your position=(30*sqrt(2) miles,45°)
Polar coordinates of your position=(30*sqrt(2) miles,Pi/4)</span>
4 0
3 years ago
Help again quick please!
zmey [24]

Answer:

2/3

Step-by-step explanation:

3 0
3 years ago
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I need answer ples ASAP
Lina20 [59]
Oh I know this!, 43/6
3 0
3 years ago
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