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3 years ago

Round the decimal to the nearest whole number 5.8??

2 answers:

8 0

If you want to round to the nearest whole number, the answer would be 6. Remember, if the number right after the decimal is higher than 5, you want to round up, if the number is lower that 5, you will want to round down. I hope this helped!! :)

11Alexandr11 [23.1K]3 years ago

6 0

Answer:

Step-by-step explanation:

Because 5.8 is closer to 6 than it is to 5.

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Tiana has $70 in an account. The interest rate is 5% compounded annually.

Alekssandra [29.7K]

Answer:

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Step-by-step explanation:

Initial Deposit:

Years to Save:

Estimated Rate of Return

Compound Frequency:

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2 years ago

Kyra was building a bed for her dollhouse. She used her bed, which is 4 feet × 5 feet, as a guide. She scaled down the dimension

Crank

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3 years ago

Which expression is equivalent to 3x+10−x+12 ?

Stells [14]

Answer:

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3 years ago

Read 2 more answers

An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample

valentina_108 [34]

Answer:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

Replacing we got:

$\bar X=58.875$ represent the mean

$s=5.083$ represent the sample standard deviation for the sample

$n=8$ sample size

$\mu_o =60$ represent the value that we want to test

$\alpha=0.1$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:

Null hypothesis: $\mu \geq 60$

Alternative hypothesis: $\mu < 60$

The statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info we got:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0

3 years ago

Based on data from the U.S. Census Bureau, a Pew Research study showed that the percentage of employed individuals ages 25-29 wh

makvit [3.9K]

Answer:

a.] d) employed individuals aged 25-29

b.] a) Have your earned a bachelor's degree (or higher)?

C.] Categorical

Step-by-step explanation:

According to the scenario described, the population being studied are those aged between 25 - 29 years and who are employed. The study was to determine the level of education of the respondents who happens to fall into the category of being employed and within the 25 - 29 Years age bracket.

The most appropriate question to ask in other to establish if respondent has at least a bachelor's degree is to explicitly ask if the respondent has a bachelor's degree or higher.

C) Categorical : The response to the question will best directly take a 'yes' 'no' format which is a categorical label which could then be transformed into dummy variables for further analysis

8 0

3 years ago