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3 years ago

A cookie recipe calls for 6 cups of flour

Mathematics

2 answers:

Roman55 [17]3 years ago

7 0

Answer:

1:3

Step-by-step explanation:

2:6[sugar is to flour]

1:3[to simplify divide both sides by two]

trapecia [35]3 years ago

6 0

Answer:

1:3

Step-by-step explanation:

Sugar : Flour

2 : 6 (substitute the numbers of cups)

1 : 3 (simplify by reducing. divide both sides by 2)

The ratio is 1:3.

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Which is the equation of a line that passes through the point (3.-4

gtnhenbr [62]

Answer:B

Step-by-step explanation:

A. y = 2x-11

B. y = 2x-10

c. y = 2x-4

D. y=2x-2

Recall, the slope intercept equation

y= mx+c

Assuming c is held constant in each scenario

Looking at A

m = 2, c = -11

Equation of the line that passes through the point (3.-4)

-4 = 2×3 + c

c =-10

-10 does not correspond to -11 given

Let's try B

m= 2, c = -10

Equation of the line that passes through the point (3.-4)

-4 = 2×3 + c

c = -4-6 = -10

This intercept correspond with the intercept in B which is -10

Let's look at C

m= 2, c = -4

Equation of the line that passes through the point (3.-4)

-4 = 2×3 + c

c = -4-6 = -10

-10 does not correspond to -4 given

Let's try D

m= 2, c = -2

Equation of the line that passes through the point (3.-4)

-4 = 2×3 + c

c = -4-6 = -10

-10 does not correspond to -2 given

7 0

3 years ago

What is the measure of x to the nearest degree?<br> 8

faust18 [17]

We know that :

$\sf{\bigstar \ \ Cos\theta = \dfrac{Adjacent \ Side}{Hypotenuse}}$

From the figure, We can notice that :

Ф Adjacent side length = 8

Ф Hypotenuse length = 11

$\sf{\implies Cosx^{\circ} = \dfrac{8}{11}}$

$\sf{\implies x^{\circ} = Cos^{-1}\bigg(\dfrac{8}{11}\bigg)}$

$\sf{\implies x^{\circ} = 43.34}$

7 0

3 years ago

Part 4: Use the information provided to write the vertex formula of each parabola.

sergey [27]

Answer: 1. x = (y - 2)² + 8

$\bold{2.\quad x=-\dfrac{1}{2}(y-10)^2}+1$

3. y = 2(x +9)² + 7

<u>Step-by-step explanation:</u>

Notes: Vertex form is: y =a(x - h)² + k or x =a(y - k)² + h

(h, k) is the vertex
point of vertex is midpoint of focus and directrix: $\dfrac{focus+directrix}{2}$

$\bullet\quad a=\dfrac{1}{4p}$

p is the distance from the vertex to the focus

$focus = \bigg(\dfrac{-31}{4},2\bigg)\qquad directrix: x=\dfrac{-33}{4}\\\\\text{Since directrix is x, then the x-value of the vertex is:}\\\\\dfrac{focus+directrix}{2}=\dfrac{\frac{-31}{4}+\frac{-33}{4}}{2}=\dfrac{\frac{-64}{4}}{2}=\dfrac{-16}{2}=-8\\\\\text{The y-value of the vertex is given by the focus as: 2}\\\\\text{vertex (h, k)}=(-8,2)$

Now let's find the a-value:

$p=focus-vertex\\\\p=\dfrac{-31}{4}-\dfrac{-32}{4}=\dfrac{1}{4}\\\\\\a=\dfrac{1}{4p}=\dfrac{1}{4(\frac{1}{4})}=\dfrac{1}{1}=1$

Now, plug in a = 1 and (h, k) = (-8, 2) into the equation x =a(y - k)² + h

x = (y - 2)² + 8

***************************************************************************************

$focus = \bigg(\dfrac{1}{2},10\bigg)\qquad directrix: x=\dfrac{3}{2}\\\\\text{Since directrix is x, then the x-value of the vertex is:}\\\\\dfrac{focus+directrix}{2}=\dfrac{\frac{1}{2}+\frac{3}{2}}{2}=\dfrac{\frac{4}{2}}{2}=\dfrac{2}{2}=1\\\\\text{The y-value of the vertex is given by the focus as: 10}\\\\\text{vertex (h, k)}=(1,10)$

Now let's find the a-value:

$p=focus-vertex\\\\p=\dfrac{1}{2}-\dfrac{2}{2}=\dfrac{-1}{2}\\\\\\a=\dfrac{1}{4p}=\dfrac{1}{4(\frac{-1}{2})}=\dfrac{1}{-2}=-\dfrac{1}{2}$

Now, plug in a = -1/2 and (h, k) = (1, 10) into the equation x =a(y - k)² + h

$\bold{x=-\dfrac{1}{2}(y-10)^2}+1$

***************************************************************************************

$focus = \bigg(-9,\dfrac{57}{8}\bigg)\qquad directrix: y=\dfrac{55}{8}\\\\\text{Since directrix is y, then the y-value of the vertex is:}\\\\\dfrac{focus+directrix}{2}=\dfrac{\frac{57}{8}+\frac{55}{8}}{2}=\dfrac{\frac{112}{8}}{2}=\dfrac{14}{2}=7\\\\\text{The x-value of the vertex is given by the focus as: -9}\\\\\text{vertex (h, k)}=(-9,7)$