Answer:
$ 327.08
Step-by-step explanation:
Let w be the width ( in meters ) of the container,
⇒ Length of the container = 2w,
If h be the height of the container,
So, the volume of the container = length × width × height
= 2w × w × h
= 2w² h
According to the question,
Now, the area of the base = length × width
Area of sides = 2 × length × height + 2 × width × height
Since, material for the base costs $20 per square meter and material for the sides costs $12 per square meter,
Hence, total cost,
Differentiating with respect to w,
Again differentiating with respect to w,
For maxima or minima,
C'(w) = 0
For w = 1.651, C''(w) = positive,
Thus, cost is minimum for width 1.651 meters,
And, the minimum cost = C(1.651) =