Answer:
Option (C) is correct.
Step-by-step explanation:
The given options of the possible equation for the graph are as follows:

The given graph is decreasing and at x=0, y=2.
So, first checking the value of the given options for x=0

As, for x=0, y=2, so options (C) and (D) are not possible, so rejected.
Now, checking the nature (increasing or decreasing) of the given equation by differentiating it.
For option (A),

As 
So, 
Therefore, the function in option (A) is increasing function.
Similarly, for option (C),

As 
So, 
Therefore, the function in option (C) is decreasing function.
As the given graph is decreasing, so, (C) represents
the given graph.
Hence, option (C) is correct.