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3 years ago

3/4 divided by 1/4 equal

Mathematics

2 answers:

Sedbober [7]3 years ago

8 0

Answer:

Step-by-step explanation:

you have to make 1/4 a reciprocal

3/4 times 4/1

garik1379 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

Step 1:

3/4 × 1/4 Equation

Step 2:

3/4 × 4/1 Flip Fraction

Step 3:

3/1 = 3 Multiply

Answer:

Hope This Helps :)

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A jackets original price is $65.00 .It is on sale for 40% off. you have to pay 5% sales tax What is the final price fir the jack

lesya [120]

Hello!

There is a discount of 40%, which means that we will be subtracting 40% of the price, and then sales tax is basically additional money added to the price, so we will be adding that.

65.00 * 40% = 26

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So, the discounted price is $39. Now we must add tax on that.

39 * 5% = 1.95

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Step-by-step explanation:

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3 years ago

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Determine the value of B such that the line defined by 8x + By + 92 = 0 passes through the point (-4,12).

zvonat [6]

8x + By + 92 = 0

(-4; 12) ⇒ x = -4; y = 12

subtitute

8 · (-4) + 12B + 92 = 0
-32 + 12B + 92 = 0
12B + 60 = 0 |subtract 60 from both sides
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B = -5

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2 years ago

Scaling up a 4 inch by 6 inch image by 50% results in which of the following image size

Monica [59]

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I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

$\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}$

<h3>Hence the standard form of inequality is y²+3y +2 ≤ 0 and the Solution set of the inequality is [ -2 , -1 ] .</h3>

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