I think it’s questions 1 and 2
Find the time it will take:
195 miles / 50 miles per hour = 3.9 hours.
1 hour = 60 minutes:
0.9 hours x 60 = 54 minutes.
3.9 hours = 3 hours and 54 minutes.
Add 3 hours and 54 minutes to the time it leaves:
3:30 pm + 3 hours = 6:30 PM
6:30 + 54 minutes = 7:24 PM
Answer:
B. Age of student
D. Time taken to run 1 mile
Step-by-step explanation:
From the list of given options, only B and D satisfy the required condition.
One unique determinant of continuous data is that; they are measured and not counted.
Now, let's categorize option A to D into two
1. Counted data
2. Measured data
Options that fall into the category of measured data are said to be continuous data.
A. Concert attendance; The number of people in a concert is counted
B. The age of a student is measured (in years)
C. Number of pens in a box is counted
D. Time taken to run 1 mile is measured (in units like seconds, minutes, hours, etc...)
In summary; we have
Counted
A. Concert Attendance
C. Number of pens in a box
Measured
B. Age of a student
D. Time taken to run 1 mile
Hence, the continuous data are Age of a student and Time taken to run 1 mile
1.) 3/4
2.) It snowed 1/4 more on Tuesday than it did on Monday.
Answer:
7 1/2
Step-by-step explanation:
try putting (1.6 x 7.5)+48 in a calculator i just put random numbers in the x spot until i got 60 lol
