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Alex777 [14]
3 years ago
12

At Roberta’s cafe half of her regular customers order her famous low-fat chicken sandwich. The probability of a regular customer

ordering the chicken sandwich and losing weight last month was 40%. What is the probability of someone losing weight given that they regularly ordered the sandwich?
Mathematics
1 answer:
yuradex [85]3 years ago
6 0

Answer:

The probability of losing weigth given that the sandwich was ordered is 80%.

Step-by-step explanation:

The probability of a regular costumer ordering the sandwich is said to be 50% and the probability of someone ordering that sandwich and losing weight is 40%. So we the probability of someone losing weigth if the sandwich was ordered is:

sandwich and losing weigh = (ordering sandwich)*losing weigth

losing weigth = (sandwich and losing weigth)/(ordeing sandwich)

losing wiegh = 40%/0.5 = 80%

The probability of losing weigth given that the sandwich was ordered is 80%.

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Means multiply 2 3/2×6 ok

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3 years ago
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Two buses departed simultaneously from the terminal. One travelled due south, and the other travelled due east at the rate of 2
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5km

Step-by-step explanation:

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3 years ago
In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equa
arlik [135]

Answer:

Yes. At this significance level, there is evidence to support the claim that there is a difference in the ability of the brands to absorb water.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>The significance level is 0.05.</em>

<em>The data is:</em>

<em>Brand X: 91, 100, 88, 89</em>

<em>Brand Y: 99, 96, 94, 99</em>

<em>Brand Z: 83, 88, 89, 76</em>

We have to check if there is a significant difference between the absorbency rating of each brand.

Null hypothesis: all means are equal

H_0:\mu_x=\mu_y=\mu_z

Alternative hypothesis: the means are not equal

H_a: \mu_x\neq\mu_y\neq\mu_z

We have to apply a one-way ANOVA

We start by calculating the standard deviation for each brand:

s_x^2=30,\,\,s_y^2=6,\,\,s_z^2=35.33

Then, we calculate the mean standard error (MSE):

MSE=(\sum s_i^2)/a=(30+6+35.33)/3=71.33/3=23.78

Now, we calculate the mean square between (MSB), but we previously have to know the sample means and the mean of the sample means:

M_x=92,\,\,M_y=97,\,\,M_z=84\\\\M=(92+97+84)/3=91

The MSB is then:

s^2=\dfrac{\sum(M_i-M)^2}{N-1}\\\\\\s^2=\dfrac{(92-91)^2+(97-91)^2+(84-91)^2}{3-1}\\\\\\s^2=\dfrac{1+36+49}{2}=\dfrac{86}{2}=43\\\\\\\\MSB=ns^2=4*43=172

Now we calculate the F statistic as:

F=MSB/MSE=172/23.78=7.23

The degrees of freedom of the numerator are:

dfn=a-1=3-1=2

The degrees of freedom of the denominator are:

dfd=N-a=3*4-3=12-3=9

The P-value of F=7.23, dfn=2 and dfd=9 is:

P-value=P(F>7.23)=0.01342

As the P-value (0.013) is smaller than the significance level (0.05), the null hypothesis is rejected.

There is evidence to support the claim that there is a difference in the ability of the brands to absorb water.

3 0
3 years ago
One fourth of the 120 students took wood shop. How many students did not take wood shop?
yawa3891 [41]

Answer:

90 students.

Step-by-step explanation:

Given 1/4 of the 120 students took woodshop, just take the 3/4 that didn't take it:

\frac{3}{4}(120)

Find common factors between 4 and 120 to simplify, so 4.

\frac{3}{1} (30)

Now multiple across to get 90.

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Pamela Is 10 years older than Jiri. The sum of their ages is 96. What is Jiri’s age
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43 is jiri and 53 is pamela
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