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Zolol [24]
3 years ago
14

(1 point) Suppose that for two random variables X and Y the joint density function is f(x,y)=6xe−x(y+6), for x>0 and y>0.

Find each of the following. (a) fX|Y(x,y)= (b) fY|X(x,y)=
Mathematics
1 answer:
andriy [413]3 years ago
3 0

First find the marginal distributions:

f_X(x)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dy=\int_0^\infty6e^{-x(y+6)}\,\mathrm dy

\implies f_X(x)=\begin{cases}6e^{-6x}&\text{for }x>0\\0&\text{otherwise}\end{cases}

f_Y(y)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dx=\int_0^\infty6e^{-x(y+6)}\,\mathrm dx

\implies f_Y(y)=\begin{cases}\dfrac6{(y+6)^2}&\text{for }y>0\\0&\text{otherwise}\end{cases}

Then to get each conditional distribution, divide the joint distribution by the corresponding marginal distribution.

a.

f_{X|Y}(x,y)=\dfrac{f_{X,Y}(x,y)}{f_Y(y)}=\begin{cases}x(y+6)^2e^{-x(y+6)}&\text{for }x>0\\0&\text{otherwise}\end{cases}

b.

f_{Y|X}(x,y)=\dfrac{f_{X,Y}(x,y)}{f_X(x)}=\begin{cases}xe^{-xy}&\text{for }y>0\\0&\text{otherwise}\end{cases}

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Answer:

x = -2

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Step-by-step explanation:

Given two equations

1. 7x + 10y = 36

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Substitute 2x + 9 for y in equation 1.

We have

7x + 10y = 36

7x + 10(2x + 9) = 36

Distribute 10 into (2x + 9)

We have

7x + 10 x 2x + 10 x 9 = 36

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27x + 90 = 36

Subtract 90 from both sides to eliminate 90 on the left side

27x + 90 - 90 = 36 - 90

27x = -54

Divide both sides by 27 to isolate x

27x/27 = -54/27

x = -2

Now substitute -2 into either equation to get y

Using equation 2, we have

y = 2x + 9

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Check

7(-2) + 10(5) = 36

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3 years ago
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tankabanditka [31]

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1

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1 year ago
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