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Dvinal [7]
3 years ago
13

which of the following statements best describes the effort of replacing the graph of f(x) with the graph of f(x)-3

Mathematics
1 answer:
rjkz [21]3 years ago
6 0
Move f(x) down by 3. I guess...
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What is 0.2 rounded to the nearest whole number?
REY [17]

Answer:

0

Step-by-step explanation:

since 2 isnt up to 5, it cannot equate to 1

5 0
2 years ago
Help please, finals week is upon me​
kenny6666 [7]

The circumcenter is found by finding the intersection of at least 2 perpendicular bisector segments.

Find the perpendicular bisector to segment AB. This is the line y = -3.5; the idea is that you find the equation of the horizontal line through the midpoint of AB. The midpoint has a y coordinate of -3.5. This line is shown in red horizontal line in the attached image below.

The midpoint of AC is 2.5, so the perpendicular bisector to AC is x = 2.5 which is shown as the vertical green line in the same diagram.

The red and green lines cross at the location (2.5, -3.5) which is the circumcenter's location. If you were to draw a circle through all three points A, B, & C, then this circle would be centered at (2.5, -3.5)

If point D is the circumcenter, then we know this

AD = BD = CD

basically the distance from the center to any point on the triangle is the same. This is due to the fact that all radii of the same circle are the same length.

<h3>Answer: (2.5, -3.5)</h3>

note: 2.5 in fraction form is 5/2 while -3.5 in fraction form is -7/2

6 0
3 years ago
Can someone help me with algebra? I REALLY NEED IT.
frosja888 [35]
The answer is A i believe

6 0
3 years ago
Read 2 more answers
PLEASE HELP AND ANSWER!!!!! Which of the following reveals the minimum value for the equation 2x2 + 12x − 14 = 0?
NARA [144]

Answer:

The correct option is 3.

Step-by-step explanation:

The given equation is

2x^2+12x-14=0

It can be written as

(2x^2+12x)-14=0

Taking out the common factor form the parenthesis.

2(x^2+6x)-14=0

If an expression is defined as x^2+bx then we add (\frac{b}{2})^2 to make it perfect square.

In the above equation b=6.

Add and subtract 3^2 in the parenthesis.

2(x^2+6x+3^2-3^2)-14=0

2(x^2+6x+3^2)-2(3^2)-14=0

2(x+3)^2-18-14=0

2(x+3)^2-32=0             .... (1)

Add 32 on both sides.

2(x+3)^2=32

The vertex from of a parabola is

p(x)=a(x-h)^2+k        .... (2)

If a>0, then k is minimum value at x=h.

From (1) and (2) in is clear that a=2, h=-3 and k=-32. It means the minimum value is -32 at x=-3.

The equation 2(x+3)^2=32 reveals the minimum value for the given equation.

Therefore the correct option is 3.

5 0
3 years ago
What method can be used to prove the triangles are congruent ?
RUDIKE [14]
C is the answer to the problem
6 0
2 years ago
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