Answer:
(h+7j)*(h+2j)
Step-by-step explanation:
h^2+7hj+2hj+14j^2
h*(h+7j)+2j*(h+7j)=(h+7j)*(h+2j)
If you are asking if your work is good,thn yes,you are right
Essentially, what we need to do here is prove that BE=EC, BE=CB, and.or CE=BC therefore making it isosceles. With ∠AEC=∠DEB, we know AE=DE, so EC=EB (the points go in order). Therefore, as EC=EB, BEC is isosceles (it has at least 2 equal sides).
Feel free to ask further questions!