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3 years ago

6^3+5^2= 18+5^2 true or false

Mathematics

2 answers:

algol133 years ago

7 0

Hey there!

$Answer:\boxed{\text{False}}$

$Explanation:$

$6^3+5^2=18+5^2\text{ True or False}$

The answer is False because $6^3+5^2$ is equal to 61 and $18+5^2$ is equal to 41 so it is false.

$\boxed{\text{False}}\text{ is the answer.}$

Hope this helps!

$\text{-TestedHyperr}$

BlackZzzverrR [31]3 years ago

4 0

False always do the exponent first PEMDAS. 6^3+5^2= 241 and 18+5^2 would be 18+ 25

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Can someone help me with these 5 question I have attached?

Contact [7]

Example 2: x=10

Example 3: x=-1

Example 4: x=35

Example 5: a-b+c=9

Example 6: x=1, x=1/2

Further explanation:

Example 2:

$\sqrt{4x-4} =6$

Taking Square on both sides

$(\sqrt{4x-4})^2 =(6)^2\\4x-4=36\\4x=36+4\\4x=40\\\frac{4x}{4}=\frac{40}{4}\\x=10$

Example 3:

$9+\sqrt{4x+8}=11$

Subtracting 9 from both sides

$9-9+\sqrt{4x+8}=11-9\\\sqrt{4x+8}=2\\$

Taking Square on both sides

$(\sqrt{4x+8})^2=(2)^2\\4x+8=4\\4x=4-8\\4x=-4\\\frac{4x}{4}=-\frac{4}{4}\\x=-1$

Example 4:

$8+\sqrt{x+1}=2$

subtracting 8 from both sides

$8-8+\sqrt{x+1}=2-8\\\sqrt{x+1}=-6$

Taking Square on both sides

$(\sqrt{x+1})^2=(-6)^2\\x+1=36\\$

Subtracting 1 from both sides

$x+1-1=36-1\\x=35$

Example 5:

$\sqrt{a-b+c}=3$

Taking Square on both sides

$(\sqrt{a-b+c})^2=(3)^2\\a-b+c=9\\$

Example 6:

$2\sqrt{2x-1}=4x-2$

Taking square on both sides

$(2\sqrt{2x-1})^2=(4x-2)^2\\4(2x-1)=16x^2+4-16x\\8x-4=16x^2-16x+4\\8x=16x^2-16x+4+4\\8x=16x^2-16x+8\\16x^2-16x-8x+8=0\\16x^2-24x+8=0$

dividng whole equation by 8

$2x^2-3x+1=0\\2x^2-2x-x+1=\\2x(x-1)-1(x-1)=0\\(2x-1)(x-1)=0\\2x-1=0 => x=\frac{1}{2}\\x-1=0 => x=1$

Keywords: Radical Expressions, Examples

Learn more about radical expressions at:

#LearnwithBrainly

3 0

3 years ago

Simplify. Write your answer without parentheses.

adoni [48]

Answer:

Simplifying the expression eliminating the parentheses:

(-5 u^2 w)^3 = -125 u^6 w^3

Step-by-step explanation:

(-5 u^2 w)^3 = (-5)^3 (u^2)^3 (w)^3

(-5 u^2 w)^3 = (-5)(-5)(-5) u^(2 x 3) w^3

(-5 u^2 w)^3 = -125 u^6 w^3

3 0

3 years ago

Write an equation of the line passing through the point (3, -1) and parallel to the line y=2/3x - 5. Show work

alex41 [277]

Answer:

The answer is: y = 2/3x - 3

Step-by-step explanation:

Given point: (3, -1)

Given equation: y = 2/3x - 5, which is in the form y = mx + b where m is the slope and b is the y intercept.

Parallel lines have the same slope. Use the point slope form of the equation with the point (3, -1) and substitute:

y - y1 = m(x - x1)

y - (-1) = 2/3(x - 3)

y + 1 = 2/3x - 6/3

y + 1 = 2/3x - 2

y = 2/3x - 3

Proof:

f(3) = 2/3(3) - 3

= 6/3 - 3

= 2 - 3

= -1, giving the point (3, -1)

Hope this helps! Have an Awesome Day!! :-)

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3 years ago

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mars1129 [50]

Answer:

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Step-by-step explanation:

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JulsSmile [24]

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