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2 years ago

Guys help please!!!!!

Mathematics

1 answer:

Firlakuza [10]2 years ago

7 0

Answer:

what?

Step-by-step explanation:

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If m∠ATB = 20°, m∠BTD = 72°, and m∠CTD = 38°, what is m∠ATC?

Ber [7]

Answer: m∠ATC = 54°

Step-by-step explanation:

Ok, we know that:

m∠ATB = 20° and m∠BTD = 72°

then we must have that the angle between A and D, is equal to the sum of the angles between A and B, and B and D, or:

m∠ATD = m∠ATB + m∠BTD = 20° + 72° = 92°

Now, we also know that m∠CTD = 38°

And the angle:

m∠ATC will be equal to the angle between A and D, minus the angle between C and D, or:

m∠ATC = m∠ATD - m∠CTD = 92° - 38° = 54°

7 0

2 years ago

jonathan had 72 pieces of recycling.he sorted them into 9 bins if each bin had the same amount , how many pieces of recycling we

Mkey [24]

8, 72 pieces of recycling sorted into 9 bins will make 8 in each bin.

8 0

2 years ago

Read 2 more answers

Find the face value of the 20-year zero-coupon bond at 4.4%, compounded semiannually, with a price of $8,375.

umka21 [38]

<u>Given</u>:

Time,

t = 20 years

Rate,

r = 4.4%

Price

= $8,375

Now,

The yield will be:

= $\frac{4.4}{2}$

= $1.1$ (%)

Time will be:

= $20\times 2$

= $40 \ periods$

As we know the formula,

⇒ $Price \ of \ bond = \frac{Face \ value}{(1+\frac{r}{2} )^{n\times 2}}$

By substituting the values, we get

$8375=\frac{Face \ value}{(1+\frac{0.044}{2} )^{20\times 2}}$

$8375=\frac{Face \ value}{(1.022)^{40}}$

$8375=\frac{Face \ value}{2.3880083}$

The face value will be:

$Face \ value = 2.3880083\times 8375$

$=20,000$ ($)

Learn more about face value here:

brainly.com/question/14862802

5 0

2 years ago

Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0

Masja [62]

|x| = x for x ≥ 0

examples:

|3| = 3; |0.56| = 0.56; |102| = 102

|x| = -x for x < 0

examples:

|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102

--------------------------------------------------------------------------------

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

--------------------------------------------------------------------------------

$h(x)=\dfrac{1}{3}|x-6|+4$

Put the values of x to the equation of the function h(x):

$x=-3\to h(-3)=\dfrac{1}{3}|-3-6|+4=\dfrac{1}{3}|-9|+4=\dfrac{1}{3}(9)+4=3+4=7\\\\x=-2\to h(-2)=\dfrac{1}{3}|-2-6|+4=\dfrac{1}{3}|-8|+4=\dfrac{1}{3}(8)+4=\dfrac{8}{3}+\dfrac{12}{3}=\dfrac{20}{3}\\\\x=0\to h(0)=\dfrac{1}{3}|0-6|+4=\dfrac{1}{3}|-6|+4=\dfrac{1}{3}(6)+4=2+4=6$

6 0

2 years ago

Hi everyone I'm confused with this problem and was wondering if someone could help out and explain to me what the answer is and

hjlf

The answer is C i hope this helps

4 0

2 years ago