For the ratio 28 : 36, find an equivalent with both terms greater tan 6 less than 10

Which equation can be used to solve for b? Triangle A B C is shown. Angle A C B is 90 degrees and angle C B A is 30 degrees. The

STALIN [3.7K]

Answer:

$b=(8)tan(30\°)$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle ABC, the tangent of angle of 30 degrees is equal to divide the opposite side to the angle of 30 degrees (AC) by the adjacent side to the angle of 30 degrees (BC)

$tan(30\°)=AC/BC$

substitute the given values

$tan(30\°)=b/8$

Solve for b

$b=(8)tan(30\°)$

8 0

3 years ago

Read 2 more answers

I need help with this problem <br><br> Someone explain this to me

Anton [14]

Answer:

16.5

Step-by-step explanation:

Look at the relation between the 2 sides that you have measurements for. One is 16cm, the other 24cm. This means that triangle 2 is 1.5 times larger than triangle 1. Multiply the known measurement from tringle 1, 11cm by 1.5 and you get 16.5 cm

5 0

3 years ago

Which table of values represents a linear function?

strojnjashka [21]

Answer:

B is

Step-by-step explanation:

Use function Y=ax, try it on B and you will get a=-1.

others are not linear function.

6 0

3 years ago

A rectangle has its vertices at (-4, -3), (-4,7), (1,7), (1, -3). What part, in percent, of the rectangle is located in Quadrant

Rasek [7]

Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.

To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.

A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:

$\overline{AB} = |A_y-B_y| = |-3-7| = |-10| = 10$

Similarly, but exchanging the role of x and y, we compute the length of BC:

$\overline{BC} = |B_x-C_x| = |-4-1| = |-5| = 5$

So, the area of the rectangle is $\overline{AB} \cdot \overline{BC} = 10\cdot 5 = 50$

The same procedure allows us to compute width and height of the sub-rectangle in the third quadrant:

$\overline{AE} = |A_y-E_y| = |-3-0| = |-3| = 3$

$\overline{EG} = |E_x-G_x| = |-4-0| = |-4| = 4$

So, the area of the portion located in the third quadrant is $\overline{AE} \cdot \overline{EG} = 3\cdot 4 = 12$

This means that the ratio between the two area is

$\cfrac{\text{area }AEGF}{\text{area }ABCD} = \cfrac{12}{50}$

If we want this ratio to be a percentage, just make sure that the denominator is 100:

$\cfrac{12}{50} = \cfrac{12}{50}\cdot \cfrac{2}{2} = \cfrac{24}{100} = 24\%$

3 0

3 years ago

What is 9713 rounded to the place value

Akimi4 [234]

It could be 10000,9800,or 9710

6 0

3 years ago