Hi
Answer:
Step-by-step explanation:
Answer:
The real zeros of f(x) are x = 0.3 and x = -3.3.
Step-by-step explanation:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots
such that
, given by the following formulas:
In this problem, we have that:

So

The real zeros of f(x) are x = 0.3 and x = -3.3.
Answer:
Step-by-step explanation:
x2+y2+ax+by+c=0
Step 1: Add -by to both sides.
ax+by+x2+y2+c+−by=0+−by
ax+x2+y2+c=−by
Step 2: Add -x^2 to both sides.
ax+x2+y2+c+−x2=−by+−x2
ax+y2+c=−bax+y2+c+−y2=−by−x2+−y2
ax+c=−by−x2−y2
Step 4: Add -c to both sides.
ax+c+−c=−by−x2−y2+−c
ax=−by−x2−y2−c
Step 5: Divide both sides by x.
ax
x
=
−by−x2−y2−c
x
a=
−by−x2−y2−c
x
y−x2
The graph of a function is given. It is required to find the function that represents the graph.
Notice from the graph that the function has roots or zeros at -3,-2, and 2.
Hence, the function takes the form:

Where a is a constant to be determined.
Notice that the given graph passes through the point (0,-12).
Substitute x=0 and f(x)=-12 into the equation of the function to find a:

Hence, the function is:

<h2>
The third option is the answer: f(x)=(x+2)(x+3)(x-2).</h2>
Answer:
x^2y^2 3y^2
Step-by-step explanation:
its a or the first choice