Find the equation of the line with a slope of 12 that passes through the point (3, -1).
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Answer:
maximum value of P is 33
Step-by-step explanation:
Sketch the lines represented by the constraints
5x + y = 16
with intercepts (, 0) and (0, 16)
2x + 3y = 22
with intercepts (11, 0) and (0, )
The solutions to both are below the lines.
Solve 5x + y = 16 and 2x + 3y = 22 simultaneously to find the point of intersection at (2, 6)
The coordinates of the vertices of the feasible region are
(0, 0), (0, 16), (2, 6), 11, 0)
Evaluate the objective function at each vertex
P = 3(0) + 2(0) = 0 + 0 = 0
P = 3(0) + 2(16) = 0 + 32 = 32
P = 3(2) + 2(6) = 6 + 12 = 18
P = 3(11) + 2(0) = 33 + 0 = 33
The maximum value of P is 33 when x = 11 and y = 0