Answer:
i tried the math and if im correct it should be 0.52N
Step-by-step explanation:
im sorry if its not correct bro
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
27 degrees add four then 23 and you get 27
Answer:
45,796 feet squared, assuming the length of one side is 214 feet.
Step-by-step explanation:
H(1) = 4
h(1)= 5 x 1 -1
=5-1
=4
hope that helps <3