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lubasha [3.4K]
4 years ago
6

GEOMETRY: Help asap pls - show all work

Mathematics
1 answer:
Elina [12.6K]4 years ago
3 0

Find the distance between the points to the nearest tenth.

1. C(-1, -1), D(6, 2)

\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

=\sqrt{\left(6-\left(-1\right)\right)^2+\left(2-\left(-1\right)\right)^2}

=\sqrt{58}

<h3>= 7.6</h3>

2. E(-7, 0), F(5 ,8)

=\sqrt{\left(5-\left(-7\right)\right)^2+\left(8-0\right)^2}

=4\sqrt{13}

=3(3.6)

<h3>=10.8</h3>

______________________________________________________

AB has endpoints A(-3, 2) and B(3, -2).

3. find the coordinates of the midpoint of Line AB

\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

=\left(\frac{3-3}{2},\:\frac{-2+2}{2}\right)

=\left(0,\:0\right)

4. Find AB to the nearest tenth

AB = \sqrt{\left(3-\left(-3\right)\right)^2+\left(-2-2\right)^2}

AB =2\sqrt{13}

AB =2(3.6)

<h3>AB = 7.2 units.</h3>
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