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gayaneshka [121]

2 years ago

13

Evaluate 46.32 You may complete your work offline to show your thinking.

1 answer:

Katena32 [7]2 years ago

6 0

Answer:

you want me to round it I will edit it and show you

Step-by-step explanation:

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A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer

Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

$L_A \to$ length of play area A

$W_A \to$ width of play area A

$L_B \to$ length of play area B

$W_B \to$ width of play area B

$x \to$ Area of A

$y \to$ Area of B

From the question, we have the following:

$L_A = 1 + 4W_A$

$W_B = 2 + W_A$

$L_B = 2 + 3W_B$

$x = y$

The area of A is:

$x = L_A * W_A$

This gives:

$x = (1 + 4W_A) * W_A$

Open bracket

$x = W_A + 4W_A^2$

The area of B is:

$y = L_B * W_B$

$y = (2 + 3W_B) * ( 2 + W_A)$

Substitute: $W_B = 2 + W_A$

$y = (2 + 3(2 + W_A)) * ( 2 + W_A)$

Open brackets

$y = (2 + 6 + 3W_A) * ( 2 + W_A)$

$y = (8 + 3W_A) * ( 2 + W_A)$

Expand

$y = 16 + 8W_A + 6W_A + 3W_A^2$

$y = 16 + 14W_A + 3W_A^2$

We have that:

$x = y$

This gives:

$W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2$

Collect like terms

$4W_A^2 - 3W_A^2 + W_A -14W_A - 16 =0$

$W_A^2 -13W_A - 16 =0$

Using quadratic calculator, we have:

$W_A = -14.1$ or $W = 1.13$ --- approximated

But the width can not be negative; So:

$W = 1.19$

7 0

2 years ago

Solve: -18 = -3x + 6

Stella [2.4K]

Let's start by moving all like terms to their own sides:

-18 = -3x + 6

3x = 6 + 18

3x = 24

x = 8

8 0

3 years ago

Read 2 more answers

We know that Martin is buying some apples at $0.75 each and two dozen oranges

Daniel [21]

Step-by-step explanation:

0.75a + 2(0.90) = 27.60

is the correct answer

8 0

2 years ago

20-{3+2[20÷4×5]}+16= -17 but I have to show how I got this.

aleksandr82 [10.1K]

20-{3+2(5*5)}+16

=20-{3+2*25}+16

=20-(3+50)+16

=20-53+16

=36-53

=-17

7 0

2 years ago

Point R on the coordinate grid below shows the location of a car in a parking lot. A second car needs to park 7 units above R to

Levart [38]

Answer:

it's (2,3)

Step-by-step explanation:

5 0

2 years ago