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Tatiana [17]
3 years ago
7

Sing acts are 5 min long and comedy acts are 3 min long. The show has 12 acts and last 50 min. How many singing acts and how man

y comedy acts are in the show?
Mathematics
1 answer:
ryzh [129]3 years ago
6 0

Answer

so there are 7 singing acts and 5 comedy acts.

Step-by-step explanation:

Let x= number of singing acts.

Let y= number of comedy acts.

We will take x+y=12 as our first equation, as there are 12 shows in total. We will take 5x+3y=50 as our second equation as there are 50 total minutes, and singing acts are 5 mins and comedy acts are 3 mins.

We solve x+y=12

Y=-x+12

We know y=-x+12, so we will substitute that for the y in the second equation.

1. Substitute 5x+3(-x+12)=50

2. Distribute 5x-3x+36=50

3. Solve 2x+36=50

2x=14

X=7

Now that we have found x, we will find y by substitute the x in 5x+3y=50 with the value, 7, that we found for x.

5(7)+3y=50

35+3y=50

3y=15

Y=5

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rjkz [21]

Answer:

x = -\frac{3}{2} or x = 1

Step-by-step explanation:

Using the zero product property, first step is to set the given equation, 2x^2 + x - 1 = 2 , to zero. Then factorise the left side.

Thus,

2x^2 + x - 1 = 2

Subtract 2 from both sides

2x^2 + x - 1 - 2 = 2 - 2

2x^2 + x - 3 = 0

Factorise the left side

2x^2 + 3x - 2x - 3 = 0

x(2x + 3) - 1(2x + 3) = 0

(x - 1)(2x + 3) = 0

Find the solution

x - 1 = 0

Or

2x + 3 = 0

x = 1

Or

2x + 3 = 0

2x = -3

x = -\frac{3}{2}

The answer is: x = 1 or x = -\frac{3}{2}

3 0
3 years ago
The perimeter of a rectangle is 338, if the ratio of the length to the width is 8:5, find the length
STALIN [3.7K]
Let the length be 8x and the width = 5x, then
Perimeter = 2(length + width) = 2(8x + 5x) = 2(13x) = 26x
338 = 26x
x = 338/26 = 13

Therefore, length = 8x = 8 x 13 = 104
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3 years ago
4x + 5 - 5x x=12<br> PLEASE ANSWER THIS ASAPPPP
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4x + 5 - 5x
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6 0
3 years ago
Eight people attend the theater "together and sit in a row with exactly eight seats. Suppose the eight people consist of three m
Nata [24]

Answer:

They can be seated in 120 differents ways.

Step-by-step explanation:

Taking into account that there are 3 couples and every couple has an specific way to sit, for simplify the exercise, every couple is going to act like 1 option and it's going to occupy 1 Place. If this happens we just need to organize 5 options (3 couples and 2 singles) in 5 Places (3 for a couple and 2 for the singles)

It means that now there are just 5 Places in the row and 5 options to organized. So the number of ways can be calculated using a rule of multiplication as:

<u>      5         </u>*<u>        4          </u>* <u>       3           </u> *  <u>        2     </u>  * <u>         1         </u> = 120

 1st place    2nd Place    3rd place        4th Place    5th Place

Because we have 5 options for the 1st Place, the three couples and the 2 singles. Then, 4 options for the second Place, 3 options for the third place, 2 for the fourth place and 1 option for the 5th place.

Finally, they can be seated in 120 differents ways.

8 0
3 years ago
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