The perimeter of the triangle with those given lengths is
Q in (-oo:+oo)
2/3 = (1/3)*q // - (1/3)*q
2/3-((1/3)*q) = 0
ddddddddd
d d
d d
(-1/3)*q+2/3 = 0 d d
d d
2/3-1/3*q = 0 // - 2/3 d d
d d
-1/3*q = -2/3 // : -1/3 d d
d d
q = -2/3/(-1/3) ddddddd dddddddd
dd dd
q = 2 dd dd
dd dddd dd
q = 2 dddddddddd dddddddddddd
Answer:
f=3/5x+2/5c
Step-by-step explanation:
Let us assume the width of the rectangle = w
Let us assume the length of the rectangle = l
Then
l = 2w
Also
Perimeter of the rectangle = 2 (l + w)
24 = 2 (2w + w)
24 = 2 (3w)
24 = 6w
w = 24/6
= 4 inches
Now
The length of the rectangle = 2w
= 2 * 4 inches
= 8 inches
So the length of the rectangle is 8 inches and the width is 4 inches.