Answer:
x=28
Step-by-step explanation:
We can use proportions to solve this problem. Put the side of the small triangle over the side of the large triangle.
x 42
------ = ----------
x+10 42+15
x 42
------ = ----------
x+10 57
Solve using cross products
57x = 42(x+10)
Distribute
57x = 42x+420
Subtract 42x from each side
57x-42x = 42x-42x+420
15x = 420
Divide by 15
15x/15 = 420/15
x=28
Answer:
5/2
Step-by-step explanation:
ratio of sides=(√25)/(√4)=5/2
Count the squares in between each letter.
Point Q is 6 units from Point R
Point R is 7 units from Point T
Point T is 3 units from Point S
For the area, it is easiest to take the area of each of those shapes and then add them.
(3*7/2) + (6*7)
10.5 + 42 = 52.5 Square Units
Answer:
The solution of |3x-9|≤15 is [-2;8] and the solution |2x-3|≥5 of is (-∞,2] ∪ [8,∞)
Step-by-step explanation:
When solving absolute value inequalities, there are two cases to consider.
Case 1: The expression within the absolute value symbols is positive.
Case 2: The expression within the absolute value symbols is negative.
The solution is the intersection of the solutions of these two cases.
In other words, for any real numbers a and b,
- if |a|> b then a>b or a<-b
- if |a|< b then a<b or a>-b
So, being |3x-9|≤15
Solving: 3x-9 ≤ 15
3x ≤15 + 9
3x ≤24
x ≤24÷3
x≤8
or 3x-9 ≥ -15
3x ≥-15 +9
3x ≥-6
x ≥ (-6)÷3
x ≥ -2
The solution is made up of all the intervals that make the inequality true. Expressing the solution as an interval: [-2;8]
So, being |2x-3|≥5
Solving: 2x-3 ≥ 5
2x ≥ 5 + 3
2x ≥8
x ≥8÷2
x≥8
or 2x-3 ≤ -5
2x ≤-5 +3
2x ≤-2
x ≤ (-2)÷2
x ≤ -2
Expressing the solution as an interval: (-∞,2] ∪ [8,∞)
Answer:
11
Step-by-step explanation:
9+9+11+15 is 44 44/4 is 11
