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2 years ago

14

PLEASE HELP NTH TERM MATHS

2 answers:

Taya2010 [7]2 years ago

8 0

The correct answer is n²+3.

Explanation:
We find the first differences between terms:
7-4=3; 12-7=5; 19-12=7; 28-19=9.

Since these are different, this is not linear.

We now find the second differences:
5-3=2; 7-5=2; 9-7=2.

Since these are the same, this sequence is quadratic.
We use (1/2a)n², where a is the second difference:
(1/2*2)n²=1n².

We now use the term number of each term for n:
4 is the 1st term; 1*1²=1.
7 is the 2nd term; 1*2²=4.
12 is the 3rd term; 1*3²=9.
19 is the 4th term; 1*4²=16.
28 is the 5th term: 1*5²=25.

Now we find the difference between the actual terms of the sequence and the numbers we just found:

4-1=3; 7-4=3; 12-9=3; 19-16=3; 28-25=3.

Since this is constant, the sequence is in the form (1/2a)n²+d;
in our case, 1n²+d, and since d=3, 1n²+3.

fredd [130]2 years ago

4 0

Answer:

odd numbers

Step-by-step explanation:

4 - 7 is 3, 7 - 12 is 5, 12 - 19 is 7, 19 to 28 is 9

So just keep counting

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