Answer: 5
Step-by-step explanation:
8+2=10
10/2=5
Answer:
Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f. A function f is odd if the graph of f is symmetric with respect to the origin. Algebraically, f is odd if and only if f(-x) = -f(x) for all x in the domain of f.
Step-by-step explanation:
Answer:
<em>T</em><em>H</em><em>E</em><em> </em><em>S</em><em>C</em><em>A</em><em>L</em><em>E</em><em> </em><em>F</em><em>A</em><em>C</em><em>T</em><em>O</em><em>R</em><em> </em><em>O</em><em>F</em><em> </em><em>S</em><em>C</em><em>U</em><em>L</em><em>P</em><em>T</em><em>U</em><em>R</em><em>E</em><em> </em><em>T</em><em>O</em><em> </em><em>M</em><em>O</em><em>D</em><em>A</em><em>L</em><em>=</em><em>7</em><em>:</em><em>1</em>
<em>A</em><em>S</em><em> </em><em>4</em><em>2</em><em>:</em><em>6</em><em>=</em><em>7</em><em>:</em><em>1</em><em>,</em><em>5</em><em>6</em><em>:</em><em>8</em><em>=</em><em>7</em><em>:</em><em>1</em><em>,</em><em>3</em><em>5</em><em>:</em><em>5</em><em>=</em><em>7</em><em>:</em><em>1</em>
Answer:
I don't use Geogebra, but the following procedure should work.
Step-by-step explanation:
Construct a circle A with point B on the circumference.
- Use the POINT and SEGMENT TOOLS to create a circle with centre B and radius BA.
- Use the POINT tool to mark points D and E where the circles intersect.
- Use the SEGMENT tool to draw segments from C to D, C to E, and D to E.
You have just created equilateral ∆CDE inscribed in circle A.
Answer:
d= -16
Step-by-step explanation:
To answer this question you'll have to first simplify the equation to
0.2d+-1.2=0.3d+5-3+0.1d
then combining like terms you get
0.2d-1.2=(0.3d+0.1d)+(5+-3)
0.2d-1.2=0.4d+2
then subtract 0.4d from both sides leaving you with
-0.2d-1.2=2
then add 1.2 to both sides
-0.2d=3.2
after you divide both sides by -0.2
leaving you with the answer
D= -16
