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3 years ago

There are 4 grams of fiber in 1/2 cups of oats. how many grams of fiber are in 3 1/2 cups of oats?

Mathematics

2 answers:

jarptica [38.1K]3 years ago

6 0

The answer is 12 i think

Oliga [24]3 years ago

3 0

I got 28 grams for this one............

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Please help. Approximately how many cubic feet of water does she need?

maria [59]

Answer:

The amount of water she needs to pump in:

V = Base area x Height x 1/2 = (4/2)^2 x pi x 0.75 x 1/2 = 1.5pi = ~4.7 (ft3)

=> Option D is correct.

Hope this helps!

3 0

3 years ago

SOMEONE PLEASEEEEW HELP ME OUTTT

garik1379 [7]

Answer:

By Double splitting method

=> 2x²-7x+5

=> 2x²-2x-5x+5

=>2x(x-1)-5(x-1)

x=5/2
x=1

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Hope it helps

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3 years ago

Prove how they are congruent. Geometry:SSS

Andrej [43]

The additional information needed to prove that both triangles are congruent by the SSS Congruence Theorem would be: C. HJ ≅ LN

Recall:

Based on the Side-Side-Side Congruence Theorem, (SSS), two triangles can be said to be congruent to each other if they have three pairs of congruent sides.

Thus, in the two triangles given, the two triangles has:

Two pairs of congruent sides - HI ≅ ML and IJ ≅ MN

Therefore, an additional information needed to prove that both triangles are congruent by the SSS Congruence Theorem would be: C. HJ ≅ LN

Learn more about SSS Congruence Theorem on:

brainly.com/question/4280133

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3 years ago

Read 2 more answers

What fraction of each gallon of purple paint is red paint?

motikmotik

Answer:

4/7

Step-by-step explanation:

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3 years ago

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

We dont know the true proportion, so we use $\pi = 0.5$ , which is when we are are going to need the largest sample size.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.04\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.04}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2$

$n = 600.25$

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}$