Answer:
a) point estimate is 30%
b) null and alternative hypothesis would be
: p=27%
: p>27%
c) We reject the null hypothesis, percentage working people aged 65-69 had increased
Step-by-step explanation:
<em>a. </em>
Point estimate would be the proportion of the working people aged 65–69 to the sample size and equals
ie 30%
<em>b.</em>
Let p be the proportion of people aged 65–69 who is working. OECD claims that percentage working had increased. Then null and alternative hypothesis would be
: p=27%
: p>27%
<em>c.</em>
z-score of the sample proportion assuming null hypothesis is:
where
- p(s) is the sample proportion of working people aged 65–69 (0.3)
- p is the proportion assumed under null hypothesis. (0.27)
- N is the sample size (600)
then z=
= 1.655
Since one tailed p value of 1.655 = 0.048 < 0.05, sample proportion is significantly different than the proportion assumed in null hypothesis. Therefore we reject the null hypothesis.
It’s 60 I think hope this helps
It looks like the first thing you have to find is their GCF, ya reckon ?
The factors of 56 are 1, 2, 4, 7, 8, 13, 28, and 56 .
The factors of 64 are 1, 2, 4, 8, 16, 32, and 64 .
The common factors are 1, 2, 4, and 8 .
The greatest one is 8 .
56/8 = 7
64/8 = 8
56 plus 64 = (8 times 7) plus (8 times 8)
<span>56 plus 64 = </span><u>8 times (7 plus 8)</u><span> <== that's the answer</span>
Check it out:
<span>56 plus 64 = </span><u>120</u>
<span>8 times (7 plus 8) = 8 times 15 = </span><u>120</u><span> </span>
Answer:
36 x 2 - 49 y 2
Step-by-step explanation:
6 x (6x) +6 x ( - 7 y ) + 7 y (6x) +7 y ( - 7 y)
Answer:
60%
Step-by-step explanation:
Divide the amount of people who showed up by the total invited...
39/65 = 0.6
To convert a decimal to a percent, multiply the decimal by 100%...
0.6(100%) = 60%