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ivolga24 [154]
2 years ago
13

What is the slope of the graph shown below?

Mathematics
1 answer:
-BARSIC- [3]2 years ago
3 0
-2 this is because common sense if it’s going down it’s going to be a negative plus it goes down 2 y every 1 x
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Number of females = f
Total number of people in audience = n

0.4n = f
f + (f+ 100) = n
2f + 100 = n

Find n:
f = 0.4n --> Replace f with 0.4n in the equation 2f +100 = n

2(0.4n) + 100 = n --> Multiply out the brackets
0.8n + 100 = n --> Subtract 0.8n from both sides
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n = 500

There were 500 people in the audience.
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( 3x 1/10) + ( 6x 1/100) +( 8x 1/000
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Geometry; Inscribed Angles.Find the value of y. Please explain!
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A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

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The square root of 256 is 16 and since its a square all sides are equal so the length of the room is 16 ft...
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