Given that Jon said,
"m-1 is always greater than 1-m"
we want to find how true the statement is;

secondly for negative values of m;

So, the statement "m-1 is always greater than 1-m" is false.
Because 1- m is greater than m-1 when m is a negative integer.
Therefore, I Disagree, because 1- m is greater than m-1 when m is a negative integer
The answer is -80, i have done all the math and -80 is the answer
Answer:
√36 = 6
a^2 + b^2 = c^2
6^2 + 6^2 = c^2
36 + 36 = c^2
72 = c^2
√72 = c
2 36
2 18
2 9
3 3
6√2 = c
6√2 = (estimate rounded up, 8.49)