What is the area of a rectangle with a length of 7.5 feet and a width of 8 feet?
2 answers:
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Answer:
isosceles trapezoid
Step-by-step explanation:
1) find the distance of the points
AB =
BC = |7-4| = 3
CD =
AD = |9-2| = 7
2) equation of the line that passes threw BC
y = 7
3) equation of the line that passes threw AD
y = 5
conclusion
the quadrilateral has two parallel sides and two congruent sides, so it is a isosceles trapezoid
