Have you learnt about prime numbers yet? 5 is a prime number so you can't break it up into smaller numbers other than obviously 5*1. 39 is not a prime number. At first glance you should be able to tell that its a multiple of 3 right?
39=3*13
Now you have smaller numbers.
3*13*5=13*15.
I guess that's what the answer is.
It would be H because 13 has no factors other than 1, and 13.
Hope this helps!
<span>2.66666667 !!!!!!!!!!!!!!!!!</span>
Answer:
f(-2) = 54
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 3x(x² + 4x - 5)
f(-2) is x = -2
<u>Step 2: Evaluate</u>
- Substitute in <em>x </em>[Function]: f(-2) = 3(-2)[(-2)² + 4(-2) - 5]
- [Brackets] Evaluate exponents: f(-2) = 3(-2)[4 + 4(-2) - 5]
- [Brackets] Multiply: f(-2) = 3(-2)[4 - 8 - 5]
- [Brackets] Subtract: f(-2) = 3(-2)[-4 - 5]
- [Brackets] Subtract: f(-2) = 3(-2)(-9)
- Multiply: f(-2) = -6(-9)
- Multiply: f(-2) = 54