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Katen [24]
3 years ago
5

5/8+3/4 -2/3-5/6 solve

Mathematics
2 answers:
nata0808 [166]3 years ago
8 0

Answer:

-1/8

Step-by-step explanation:

5

8

+

3

4

−

2

3

−

5

6

Step2247 [10]3 years ago
3 0

Answer:  -1/8 hope this helps

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Write the equation in slope intercept form. 5x + 3y = 6​
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3 years ago
P(k)=a^k=2 3 4 find value of a that makes this is a valid probability distribution
Vesna [10]
Sounds like you're asked to find a such that

\displaystyle\sum_{k=2}^4\mathbb P(k)=\mathbb P(2)+\mathbb P(3)+\mathbb P(4)=1

In other words, find a that satisfies

a^2+a^3+a^4=1

We can factorize this as

a^4+a^3+a^2-1=a^3(a+1)+(a-1)(a+1)=(a+1)(a^3+a-1)=0

In order that \mathbb P(k) describes a probability distribution, require that \mathbb P(k)\ge0 for all k, which means we can ignore the possibility of a=-1.

Let a=y+\dfrac xy.

a^3+a-1=\left(y+\dfrac xy\right)^3+\left(y+\dfrac xy\right)-1=0
\left(y^3+3xy+\dfrac{3x^2}y+\dfrac{x^3}{y^3}\right)+\left(y+\dfrac xy\right)-1=0

Multiply both sides by y^3.

y^6+3xy^4+3x^2y^2+x^3+y^4+xy^2-y^3=0

We want to find x\neq0 that removes the quartic and quadratic terms from the equation, i.e.

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so the cubic above transforms to

y^6-y^3-\dfrac1{27}=0

Substitute y^3=z and we get

z^2-z-\dfrac1{27}=0\implies z=\dfrac{9+\sqrt{93}}{18}
\implies y=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}
\implies a=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}-\dfrac13\sqrt[3]{\dfrac{18}{9+\sqrt{93}}}
6 0
4 years ago
Sam wants to write an equation to represent a proportional relationship with a constant of proportionality of 6. He writes the e
Volgvan

Answer:

No

Step-by-step explanation:

The COP is always the coefficient

ex. y=6x the COP is 6

3 0
3 years ago
Read 3 more answers
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