Answer:
Step-by-step explanation:
'x = -3', when graphed, passes through the point (-3,7) and (-3,0).
Since the line passes (-3,0), the x-intercept is -3.
(-3, 7) lies on the equation.
I have attached a picture of the graphed equation.
'x = -3' should be the correct answer.
now, we get critical points from zeroing out the derivative, and also from zeroing out the denominator, but those at the denominator are critical points where the function is not differentiable, namely a sharp spike or cusp or an asymptote.
so, from zeroing out the derivative we get no critical points there, from the denominator we get x = 8, but can't use it because f(x) is undefined.
therefore, we settle for the endpoints, 4 and 6,
f(4) =3 and f(6) = 7
doing a first-derivative test, we see the slope just goes up at both points and in between, but the highest is f(6), so the absolute maximum is there, while we can take say f(4) as the only minimum and therefore the absolute minumum as well.
Answer:
don't know
Step-by-step explanation:
Answer:
$132
If there are 10 friends and they each pay $12 + Amanda they will pay $132 in total
