What is 7 11 as a decimal rounded to 3 decimal places?
1 answer:
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Your question is incomplete, here is the complete form.
Points J, K and L are collinear with J between L and K. If KJ = 2x - 3, LK = 9x + 7 and LJ = 4x - 8, solve for x:
Answer:
The value of x is -6 ⇒ B
Step-by-step explanation:
∵ J, K, and L are collinear
→ That means they form a straight segment
∵ J is between K and L
→ That means J divides LK into two segments KJ and LJ
∴ LK = KJ + LJ
∵ LK = 9x + 7
∵ KJ = 2x - 3
∵ LJ = 4x - 8
→ Substitute them in the equation above
∴ 9x + 7 = (2x - 3) + (4x - 8)
→ Add the like terms in the right side
∵ 9x + 7 = (2x + 4x) + (-3 - 8)
∴ 9x + 7 = 6x + -11
∴ 9x + 7 = 6x - 11
→ Subtract 7 from both sides
∵ 9x + 7 - 7 = 6x - 11 - 7
∴ 9x = 6x - 18
→ Subtract 6x from both sides
∵ 9x - 6x = 6x - 6x - 18
∴ 3x = -18
→ Divide both sides by 3
∵
∴ x = -6
∴ The value of x is -6
The first reflection reverses the orientation and alters the direction of the vectors representing the sides of the quadrilateral. The second reflection does the same thing. The end result is that the orientation is unchanged by two reflections, and the direction of the sides of the quadrilateral is changed.
The appropriate choice is ...
... B. The resulting image will be a rotation of the pre-image.
_____
The center of rotation will be the point where the lines cross. (That is the invariant point.)
In the attachment, the green quadrilateral RESP is reflected across the line y=2x+7 (blue) to form the blue quadrilateral R'E'S'P'. That is then reflected across the line y = -12x +5 (orange) to give the orange quadrilateral R"E"S"P", which is a rotation of the pre-image.
The amount of rotation is double the angle between the lines, about 62.7°.
