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3 years ago

What is 7 11 as a decimal rounded to 3 decimal places?

Mathematics

1 answer:

nordsb [41]3 years ago

6 0

.636 o\would be the answer

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PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

skelet666 [1.2K]

-5t2 + 40t = 0
5t(-t+ 8) = 0
5t = 0 or t = 8

7 0

2 years ago

Can someone please help me?

koban [17]

Answer:

The X intercepts= 1 and -1

The y= -1

Step-by-step explanation:

It's where the line meets the axis.

7 0

2 years ago

Another 10 points if u help me :]

blagie [28]

Answer: 37

Step-by-step explanation:

4 0

2 years ago

Plz help me with this ty

Norma-Jean [14]

Answer: $0.14 per fluid ounce.

Step-by-step explanation: $4.48 divided by 32 = $0.14

4 0

2 years ago

The matrix A= (−3 0 1, 2 −4 2, −3 −2 1) has one real eigenvalue. Find this eigenvalue, its multiplicity, and the dimension of th

Aliun [14]

Answer:

a) -4

b) 1

c) 1

Step-by-step explanation:

a) The matrix A is given by:

$A=\left[\begin{array}{ccc}-3&0&1\\2&-4&2\\-3&-2&1\end{array}\right]$

to find the eigenvalues of the matrix you use the following:

$det(A-\lambda I)=0$

where lambda are the eigenvalues and I is the identity matrix. By replacing you obtain:

$A-\lambda I=\left[\begin{array}{ccc}-3-\lambda&0&1\\2&-4-\lambda&2\\-3&-2&1-\lambda\end{array}\right]$

and by taking the determinant:

$[(-3-\lambda)(-4-\lambda)(1-\lambda)+(0)(2)(-3)+(2)(-2)(1)]-[(1)(-4-\lambda)(-3)+(0)(2)(1-\lambda)+(2)(-2)(-3-\lambda)]=0\\\\-\lambda^3-6\lambda^2-12\lambda-16=0$

and the roots of this polynomial is:

$\lambda_1=-4\\\\\lambda_2=-1+i\sqrt{3}\\\\\lambda_3=-1-i\sqrt{3}$

hence, the real eigenvalue of the matrix A is -4.

b) The multiplicity of the eigenvalue is 1.

c) The dimension of the eigenspace is 1 (because the multiplicity determines the dimension of the eigenspace)

3 0

2 years ago